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Date May 2018 Marks available 1 Reference code 18M.2.SL.TZ2.6
Level Standard level Paper Paper 2 Time zone 2
Command term Show that Question number 6 Adapted from N/A

Question

Rhodium-106 ( 45 106 Rh ) decays into palladium-106 ( 46 106 Pd ) by beta minus (β) decay.

The binding energy per nucleon of rhodium is 8.521 MeV and that of palladium is 8.550 MeV.

β decay is described by the following incomplete Feynman diagram.

Rutherford constructed a model of the atom based on the results of the alpha particle scattering experiment. Describe this model.

[2]
a.

State what is meant by the binding energy of a nucleus.

[1]
b.i.

Show that the energy released in the β decay of rhodium is about 3 MeV.

[1]
b.ii.

Draw a labelled arrow to complete the Feynman diagram.

[1]
c.i.

Identify particle V.

[1]
c.ii.

Markscheme

«most of» the mass of the atom is confined within a very small volume/nucleus

«all» the positive charge is confined within a very small volume/nucleus

electrons orbit the nucleus «in circular orbits»

[2 marks]

a.

the energy needed to separate the nucleons of a nucleus

OR

energy released when a nucleus is formed from its nucleons

 

Allow neutrons AND protons for nucleons

Don’t allow constituent parts

[1 mark]

b.i.

Q = 106 × 8.550 − 106 × 8.521 = 3.07 «MeV»

«≈ 3 Me V»

[1 mark]

b.ii.

line with arrow as shown labelled anti-neutrino/ v ¯

 

Correct direction of the “arrow” is essential

The line drawn must be “upwards” from the vertex in the time direction i.e. above the horizontal

M18/4/PHYSI/SP2/ENG/TZ2/06.c.i/M

[1 mark]

c.i.

V = W

[1 mark]

c.ii.

Examiners report

[N/A]
a.
[N/A]
b.i.
[N/A]
b.ii.
[N/A]
c.i.
[N/A]
c.ii.

Syllabus sections

Core » Topic 7: Atomic, nuclear and particle physics » 7.2 – Nuclear reactions
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