Date | November 2016 | Marks available | 2 | Reference code | 16N.3.HL.TZ0.19 |
Level | Higher level | Paper | Paper 3 | Time zone | 0 - no time zone |
Command term | Show that | Question number | 19 | Adapted from | N/A |
Question
The linear attenuation coefficient μ of a material is affected by the energy of the X-ray beam and by the density ρ of the material. The mass absorption coefficient is equal to to take into account the density of the material.
The graph shows the variation of mass absorption coefficient with energy of the X-ray beam for both muscle and bone.
Show that the attenuation coefficient for bone of density 1800 kg m–3, for X-rays of 20 keV, is about 7 cm–1.
The density of muscle is 1200 kg m–3. Calculate the ratio of intensities to compare, for a beam of 20 keV, the attenuation produced by 1 cm of bone and 1 cm of muscle.
Suggest why more energetic beams of about 150 keV would be unsuitable for imaging a bone–muscle section of a body.
Markscheme
reads value on graph at 20 keV as 4 «cm2 g–1»
«4 cm2 g–1 × 1800 kg m–3 × = » 7.2 «cm–1»
Ensure that the calculation has right POT conversion.
Answer must be to at least two significant figures.
ALTERNATIVE 1
(finds intensity ratios for muscle and bone separately)
Watch for ECF
for muscle: obtains μ = 0.96 cm−1
Allow answers in the range of 0.90 to 1.02 cm–1.
= e−μx so for muscle 0.38
Allow answers in the range of 0.36 to 0.41.
Allow answers in dB. Muscle -4dB, Bone -30 or -31dB
for bone: = 7.5 × 10−4 «if μ = 7.2 is used»
OR
9.1×10−4 «if μ=7 is used»
ALTERNATIVE 2
for muscle: obtains μ = 0.96 cm−1
Allow answers in the range of 0.90 to 1.02 cm–1.
Frequently the POT will be incorrect for MP1. Allow ECF from MP1 to MP2.
Allow +/- 26 or 27dB
Award [2 max] if μ=960 as they will get = 0.
ratio is about 500 «513»
Allow range 395 to 546
If 7 used, ratio is about 420, if 7.2 is used, ratio is about 510
Allow answer IBONE/IMUSCLE from a range 0.0017 to 0.0026.
similar absorption so poor contrast