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Date November 2020 Marks available 1 Reference code 20N.3.hl.TZ0.12
Level HL Paper 3 Time zone TZ0
Command term Outline Question number 12 Adapted from N/A

Question

1.57% of the mass of a rock weighing 46.5kg is uranium(IV) oxide, UO299.28% of the uranium atoms in the rock are uranium-238, U238.

Show that the mass of the 238U isotope in the rock is 0.639kg.

[2]
a.

The half-life of 238U is 4.46×109 years. Calculate the mass of 238that remains after 0.639kg has decayed for 2.23×1010 years.

[2]
b.

Outline a health risk produced by exposure to radioactive decay.

[1]
c.

Deduce the nuclear equation for the decay of uranium-238 to thorium-234.

[1]
d.

Thorium-234 has a higher binding energy per nucleon than uranium-238. Outline what is meant by the binding energy of a nucleus.

[1]
e.

Determine the nuclear binding energy, in J, of U238 using sections 2 and 4 of the data booklet.

The mass of the U238 nucleus is 238.050786amu.

[3]
f.

Markscheme

«mass%fraction of U in UO2=»238.03238.03+2×16 /0.881/88.1% ✔

46.5«kg»×0.0157×0.881×0.9928«=0.639kg» ✔

Award [1 max] for omitting mass composition (giving 0.725kg).

M2 is for numerical setup, not for final value of 0.639kg.

a.

Alternative 1
«2.23×1010 year4.46×109 year=»5.00«half-lives» ✔

«m=0.639kg×(0.5)5=»0.0200«kg» ✔


Alternative 2
«𝜆=ln24.46×109 year=»1.554×1010«year1» ✔

«m=0.639kg×𝑒1.554×1010 year1×2.23×1010 year=»0.0200«kg» ✔


Award [2] for correct final answer.

b.

Any one:

«genetic» mutations ✔

«could cause» cancer ✔
Accept specific named types of cancer.

cells «in body» altered ✔

cells «in body» cannot function ✔

damaged DNA/proteins/enzymes/organs/tissue ✔

«radiation» burns ✔

hair loss ✔

damage in foetuses ✔

damages/weakens immune system ✔

 

c.

U92238Th90234+He24 ✔

Do not penalize missing atomic numbers in the equation.

Accept “α” for "He”.

d.

energy required to separate a nucleus into protons and neutrons/nucleons
OR
energy released when nucleus was formed from «individual/free/isolated» protons and neutrons/nucleons ✔


Do not accept “energy released when atom was formed”.

e.

238.050786«amu»×1.66×1027«kgamu1»
OR

 ✔

92×1.672622×1027+146×1.674927×10273.95×1025
OR
3.42×1027/3×1027«kg» ✔

«E=mc2=3.42×1027×(3.00×108)2=»3.08×1010«J» ✔


Accept answers in the range “2.7×10103.1×1010«J»”.

Award [3] for correct final answer.

f.

Examiners report

This question was generally well answered. Many candidates approached this question using amount, in mol, and converting to mass at the end. Some candidates omitted the mass composition however, resulting in a mass of 0.725 kg, which yielded [1 max].

a.

The question involving half-life was very well answered and most scored both marks giving a final answer of 0.0200 kg, via different methods of calculation.

b.

This question on outlining a health risk produced by exposure to radioactive decay posed no difficulty and the most common, correct answers included "could cause cancer" and "can damage DNA".

c.

Most scored the one mark for the nuclear equation for the decay of uranium-238 to thorium-234. The most common error was including a neutron on the product side

d.

Although many scored the one mark for outlining what is meant by the binding energy of a nucleus, the question was often answered as energy involved in the formation of an atom. Some candidates did not understand the difference between nucleus and nucleons.

e.

This demanding question on the determination of the nuclear binding energy was well executed and many scored all three marks. Even the weaker candidates still managed to gain an ECF mark for M3 by using the E = mc2 equation. The general performance on this type of calculation was much better than in previous sessions.

f.

Syllabus sections

Options » C: Energy » C.3 Nuclear fusion and fission
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