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Date May 2013 Marks available 4 Reference code 13M.3dm.hl.TZ0.3
Level HL only Paper Paper 3 Discrete mathematics Time zone TZ0
Command term Determine Question number 3 Adapted from N/A

Question

When numbers are written in base n, \({33^2} = 1331\).

By writing down an appropriate polynomial equation, determine the value of n.

[4]
a.

Rewrite the above equation with numbers in base 7.

[6]
b.

Markscheme

the equation can be written as

\({(3n + 3)^2} = {n^3} + 3{n^2} + 3n + 1\)     M1A1

any valid method of solution giving n = 8     (M1)A1

Note: Attempt to change at least one side into an equation in n gains the M1.

 

[4 marks]

a.

METHOD 1

as decimal numbers,

\({(33)_8} = 27,{\text{ }}{(1331)_8} = 729\)     A1A1

converting to base 7 numbers,

\(27 = {(36)_7}\)     A1

7)729     M1
7)104(1
7) 14(6
7)   2(0
7)   0(2

therefore \(729 = {(2061)_7}\)     A1

the required equation is

\({36^2} = 2061\)     A1 

METHOD 2

as a decimal number, \({(33)_8} = 27\)     A1

converting to base 7,

\(27 = {(36)_7}\)     A1

multiplying base 7 numbers

   36
× 36
1440     M1
  321     A1
2061     
A1

the required equation is

\({36^2} = 2061\)     A1

Note: Allow M1 for showing the method of converting a number to base 7 regardless of what number they convert.

 

[6 marks]

b.

Examiners report

Part (a) was a good indicator of overall ability. Many candidates did not write both sides of the equation in terms of n and thus had an impossible equation, which should have made them realise that they had a mistake. The answers that were given in (a) and (b) could have been checked, so that the candidate knew they had done it correctly.

a.

Part (b) was not well answered and of those candidates that did, some only gave one side of the equation in base 7. The answers that were given in (a) and (b) could have been checked, so that the candidate knew they had done it correctly.

b.

Syllabus sections

Topic 10 - Option: Discrete mathematics » 10.5 » Representation of integers in different bases.

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