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Date November 2010 Marks available 4 Reference code 10N.2.hl.TZ0.2
Level HL only Paper 2 Time zone TZ0
Command term Find Question number 2 Adapted from N/A

Question

The company Fresh Water produces one-litre bottles of mineral water. The company wants to determine the amount of magnesium, in milligrams, in these bottles.

A random sample of ten bottles is analysed and the results are as follows:

6.7, 7.2, 6.7, 6.8, 6.9, 7.0, 6.8, 6.6, 7.1, 7.3.

Find unbiased estimates of the mean and variance of the amount of magnesium in the one-litre bottles.

Markscheme

\(\bar m = \frac{{6.7 + 7.2 + \ldots + 7.3}}{{10}} = 6.91\)     (M1)A1

\(s_{n - 1}^2 = \frac{1}{9}\left( {{{(6.7 - 6.91)}^2} + \ldots + {{(7.3 - 6.91)}^2}} \right)\)     (M1)

\( = \frac{{0.489}}{9} = 0.0543{\text{ (3 sf)}}\)     A1

Note: Award M1A0 for 0.233.

 

[4 marks]

Examiners report

Most candidates used a GDC to answer this question and many scored full marks in this question. However there were a significant number of candidates who showed little understanding of the meaning of unbiased estimate. In some cases, candidates wasted time by attempting to calculate the required values by hand.

Syllabus sections

Topic 7 - Option: Statistics and probability » 7.3 » Unbiased estimators and estimates.

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