| Date | May 2015 | Marks available | 2 | Reference code | 15M.2.hl.TZ2.1 |
| Level | HL only | Paper | 2 | Time zone | TZ2 |
| Command term | Find | Question number | 1 | Adapted from | N/A |
Question
In triangle \({\text{ABC}}\), \({\text{AB}} = 5{\text{ cm}}\), \({\text{BC}} = 12{\text{ cm}}\) and \({\rm{A\hat BC}} = 100^\circ \).
Find the area of the triangle.
[2]
a.
Find \(AC\).
[2]
b.
Markscheme
\(A = \frac{1}{2} \times 5 \times 12 \times \sin 100^\circ \) (M1)
\( = 29.5{\text{ (c}}{{\text{m}}^2}{\text{)}}\) A1
[2 marks]
a.
\({\text{A}}{{\text{C}}^2} = {5^2} + {12^2} - 2 \times 5 \times 12 \times \cos 100^\circ \) (M1)
therefore \({\text{AC}} = 13.8{\text{ (cm)}}\) A1
[2 marks]
Total [4 marks]
b.
Examiners report
[N/A]
a.
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b.
