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Date May 2010 Marks available 6 Reference code 10M.2.hl.TZ1.9
Level HL only Paper 2 Time zone TZ1
Command term Solve and State Question number 9 Adapted from N/A

Question

Let f(x)=4x24xf(x)=4x24x.

(a)     State the largest possible domain for f.

(b)     Solve the inequality f(x)1.

Markscheme

(a)     x0 and x16     A1A1

 

(b)

     graph not to scale

finding crossing points     (M1)

e.g. 4x2=4x

x = 0 or x = 1     (A1)

0x1 or x>16     A1A1

Note: Award M1A1A1A0 for solving the inequality only for the case x<16.

 

[6 marks]

Examiners report

Most students were able to obtain partial marks, but there were very few completely correct answers.

Syllabus sections

Topic 2 - Core: Functions and equations » 2.7 » Solutions of g(x)f(x) .

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