Date | May 2012 | Marks available | 4 | Reference code | 12M.3.SL.TZ1.17 |
Level | Standard level | Paper | Paper 3 | Time zone | Time zone 1 |
Command term | Define and Derive | Question number | 17 | Adapted from | N/A |
Question
This question is about a magnifying glass.
(i) Define the angular magnification of a magnifying glass.
(ii) Derive an equation for the angular magnification of a magnifying glass with the image at infinity.
An object is positioned 8.00 cm from a magnifying glass of focal length 15.0 cm.
(i) Calculate the position of the image.
(ii) Calculate the linear magnification.
(iii) The image is upright and magnified. State a further property of the image.
Markscheme
(i) ratio of angle subtended by image at eye to angle subtended by object at the near point;
(ii) \({\theta _o} = \frac{{{h_o}}}{{25}}\);
\({\theta _i} = \frac{{{h_o}}}{f}\);
\(M = \frac{{{\theta _i}}}{{{\theta _o}}} = \frac{{{h_o}}}{f} \times \frac{{25}}{{{h_o}}} = \frac{{25}}{f}\);
Award [3] for use of symbol (e.g. D) to represent distance to near point (25 cm).
or
realizes object is at f;
obtains at least 1 correct angle as either \(\frac{h}{{25}}\) or \(\frac{h}{{D}}\) or \(\frac{h}{{f}}\);
shows that \(M = \frac{D}{f}\) or \(M = \frac{25}{f}\);
(i) \(\left( {\frac{1}{f} = \frac{1}{v} + \frac{1}{u}} \right)\)
\(\frac{1}{{15}} = \frac{1}{v} + \frac{1}{8}\);
\(v = \left( - \right)17.1{\rm{cm}}\);
(ii) 2.14 or –2.14;
(iii) virtual;