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Date May 2012 Marks available 4 Reference code 12M.3.SL.TZ1.17
Level Standard level Paper Paper 3 Time zone Time zone 1
Command term Define and Derive Question number 17 Adapted from N/A

Question

This question is about a magnifying glass.

(i) Define the angular magnification of a magnifying glass.

(ii) Derive an equation for the angular magnification of a magnifying glass with the image at infinity.

[4]
a.

An object is positioned 8.00 cm from a magnifying glass of focal length 15.0 cm.

(i) Calculate the position of the image.

(ii) Calculate the linear magnification.

(iii) The image is upright and magnified. State a further property of the image.

[4]
b.

Markscheme

(i) ratio of angle subtended by image at eye to angle subtended by object at the near point;

(ii) \({\theta _o} = \frac{{{h_o}}}{{25}}\);
\({\theta _i} = \frac{{{h_o}}}{f}\);
\(M = \frac{{{\theta _i}}}{{{\theta _o}}} = \frac{{{h_o}}}{f} \times \frac{{25}}{{{h_o}}} = \frac{{25}}{f}\);
Award [3] for use of symbol (e.g. D) to represent distance to near point (25 cm).

or

realizes object is at f;
obtains at least 1 correct angle as either \(\frac{h}{{25}}\) or \(\frac{h}{{D}}\) or \(\frac{h}{{f}}\);

shows that \(M = \frac{D}{f}\) or \(M = \frac{25}{f}\);

a.

(i) \(\left( {\frac{1}{f} = \frac{1}{v} + \frac{1}{u}} \right)\)
\(\frac{1}{{15}} = \frac{1}{v} + \frac{1}{8}\);
\(v = \left(  -  \right)17.1{\rm{cm}}\);

(ii) 2.14 or –2.14;

(iii) virtual;

b.

Examiners report

[N/A]
a.
[N/A]
b.

Syllabus sections

Option C: Imaging » Option C: Imaging (Core topics) » C.1 – Introduction to imaging
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