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Date May 2012 Marks available 4 Reference code 12M.2.SL.TZ2.9
Level Standard level Paper Paper 2 Time zone Time zone 2
Command term State Question number 9 Adapted from N/A

Question

Part 2 Gravitational fields and electric fields

The magnitude of gravitational field strength g is defined from the equation shown below.

\[g = \frac{{{F_g}}}{m}\]

The magnitude of electric field strength E is defined from the equation shown below.

\[E = \frac{{{F_E}}}{q}\]

For each of these defining equations, state the meaning of the symbols

(i) Fg.

(ii) FE.

(iii) m.

(iv) q.

[4]
a.

In a simple model of the hydrogen atom, the electron is regarded as being in a circular orbit about the proton. The magnitude of the electric field strength at the electron due to the proton is Ep. The magnitude of the gravitational field strength at the electron due to the proton is gp.

(i) Draw the electric field pattern of the proton alone.

(ii) Determine the order of magnitude of the ratio shown below.

\[\frac{{{E_p}}}{{{g_p}}}\]

[5]
b.

Markscheme

(i) the force exerted on a small/test/point mass; 
Do not allow bald “gravitational force”.

(ii) the force exerted on a small/point/test positive charge; 
To award [1] “positive” is required.
Do not allow bald “electric force”.

(iii) the size/magnitude/value of the small/point mass; 
Do not accept bald “mass”.

(iv) the magnitude/size/value of the small/point/test (positive) charge;
Do not accept bald “charge”.

a.

(i)

pattern correct with at least 8 symmetrical lines as shown;
direction correct;

(ii) \({E_p} = \frac{e}{{4\pi {\varepsilon _0}{r^2}}}\) and \({g_p} = \frac{{G{m_p}}}{{{r^2}}}\); (both needed)
\(\frac{e}{{4\pi {\varepsilon _0}G{m_p}}}\left( { = \frac{{9 \times {{10}^9} \times 1.6 \times {{10}^{ - 19}}}}{{6.7 \times {{10}^{ - 11}} \times 1.7 \times {{10}^{ - 27}}}}} \right)\);
1028 ;

b.

Examiners report

In this part candidates were completely at a loss and could not state the meanings of the symbols in the definitions of gravitational or electric field strengths. This was a disappointing failure in what was meant to be an easy opener to the whole question.

a.

(i) The diagrams presented to examiners frequently gave a clear indication of the direction and shape of the field pattern. This was well done.

(ii) Following(a) candidates failed widely on this part too. They often had little idea which data to use (mass and charge were frequently confused) and sometimes the meaning of the constants in the equations failed them too. This was compounded by arithmetic errors to make a straightforward calculation very hard for many.

b.

Syllabus sections

Core » Topic 5: Electricity and magnetism » 5.1 – Electric fields
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