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Date May 2017 Marks available 3 Reference code 17M.3.SL.TZ1.1
Level Standard level Paper Paper 3 Time zone Time zone 1
Command term Determine Question number 1 Adapted from N/A

Question

The equipment shown in the diagram was used by a student to investigate the variation with volume, of the pressure p of air, at constant temperature. The air was trapped in a tube of constant cross-sectional area above a column of oil.

The pump forces oil to move up the tube decreasing the volume of the trapped air.

The student measured the height H of the air column and the corresponding air pressure p. After each reduction in the volume the student waited for some time before measuring the pressure. Outline why this was necessary.

[1]
a.

The following graph of p versus \(\frac{1}{H}\) was obtained. Error bars were negligibly small.

The equation of the line of best fit is \(p = a + \frac{b}{H}\).

Determine the value of b including an appropriate unit.

[3]
b.

Outline how the results of this experiment are consistent with the ideal gas law at constant temperature.

[2]
c.

The cross-sectional area of the tube is 1.3 × 10–3\(\,\)m2 and the temperature of air is 300 K. Estimate the number of moles of air in the tube.

[2]
d.

The equation in (b) may be used to predict the pressure of the air at extremely large values of \(\frac{1}{H}\). Suggest why this will be an unreliable estimate of the pressure.

[2]
e.

Markscheme

in order to keep the temperature constant

in order to allow the system to reach thermal equilibrium with the surroundings/OWTTE

 

Accept answers in terms of pressure or volume changes only if clearly related to reaching thermal equilibrium with the surroundings.

[1 mark]

a.

recognizes b as gradient

calculates b in range 4.7 × 104 to 5.3 × 104

Pa\(\,\)m

 

Award [2 max] if POT error in b.
Allow any correct SI unit, eg kg\(\,\)s–2.

[3 marks]

b.

\(V \propto H\) thus ideal gas law gives \(p \propto \frac{1}{H}\)

so graph should be «a straight line through origin,» as observed

[2 marks]

c.

\(n = \frac{{bA}}{{RT}}\) OR correct substitution of one point from the graph

\(n = \frac{{5 \times {{10}^4} \times 1.3 \times {{10}^{ - 3}}}}{{8.31 \times 300}} = 0.026 \approx 0.03\)

 

Answer must be to 1 or 2 SF.

Allow ECF from (b).

[2 marks]

d.

very large \(\frac{1}{H}\) means very small volumes / very high pressures

at very small volumes the ideal gas does not apply
OR
at very small volumes some of the assumptions of the kinetic theory of gases do not hold

[2 marks]

e.

Examiners report

[N/A]
a.
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b.
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c.
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d.
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e.

Syllabus sections

Core » Topic 1: Measurements and uncertainties » 1.1 – Measurements in physics
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