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Date May 2016 Marks available 2 Reference code 16M.2.SL.TZ0.2
Level Standard level Paper Paper 2 Time zone Time zone 0
Command term Calculate Question number 2 Adapted from N/A

Question

The two arrows in the diagram show the gravitational field strength vectors at the position of a planet due to each of two stars of equal mass M.

Each star has mass M=2.0×1030kg. The planet is at a distance of 6.0×1011m from each star.

Show that the gravitational field strength at the position of the planet due to one of the stars is g=3.7×10–4Nkg–1.

[1]
a.

Calculate the magnitude of the resultant gravitational field strength at the position of the planet.

[2]
b.

Markscheme

\(g = \frac{{GM}}{{{r^2}}} = \frac{{6.67 \times {{10}^{ - 11}} \times 2.0 \times {{10}^{30}}}}{{{{\left( {6.0 \times {{10}^{11}}} \right)}^2}}}\)

OR
3.71×10-4Nkg−1  

a.

«gnet = 2cos34» 2g OR gcos34 OR gsin56 OR vector addition diagram shown

«gnet =«2×3.7×10−4 ×cos34o =» 6.1×10−4 Nkg−1

b.

Examiners report

[N/A]
a.
[N/A]
b.

Syllabus sections

Core » Topic 6: Circular motion and gravitation » 6.2 – Newton’s law of gravitation
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