average acceleration of the car in stage 1.

average net force required to accelerate the car in stage 2.

total distance travelled by the car in 12 s.

\(11{\text{ m}}{{\text{s}}^{ - 2}}\);

\(\Delta v = 236\);

\(a = \left( {\frac{{236}}{8} = } \right){\text{ }}29.5{\text{ }}\left( {{\text{m}}\,{{\text{s}}^{ - 2}}} \right)\);

\((F = 1.1 \times {10^4} \times 29.5) = 3.2 \times {10^5}{\text{ N}}\);

Award [2 max] for omission of initial speed (answer is 390 kN).

Award [3] for correct bald answer.

phase 1 distance 88 m / phase 2 distance 1296 m;

total 1400 m;

Award [2] for correct bald answer.

Watch for significant figure penalty in this question (1384 m).

Award [1 max] for \(\frac{1}{2}\)at² substituted correctly for first phase, if no distances

evaluated and answer incorrect.

Award [1 max] for correct addition of incorrect phase 1 and/or 2 distance(s).

Most candidates were able to score well on this part.

There were widespread failures to achieve the correct intermediate step of evaluating the acceleration in stage 2. The initial speed was often taken to be zero.

This very simple part caused problems for many who were unable to calculate the distances travelled in each stage, or add these together correctly.