User interface language: English | Español

Date May 2017 Marks available 1 Reference code 17M.3.hl.TZ2.26
Level HL Paper 3 Time zone TZ2
Command term Calculate Question number 26 Adapted from N/A

Question

Targeted Alpha Therapy (TAT) is a technique that involves using alpha-radiation to treat leukemia and other dispersed cancers.

Yttrium-90 and lutetium-177 are used in radiotherapy.

Explain why alpha-radiation is particularly suitable for this treatment.

[2]
a.i.

Outline how the alpha-radiation in TAT is directed to cancer cells.

[1]
a.ii.

Identify the type of radiation emitted by these two radioisotopes.

[1]
b.i.

State an equation for the one-step decay of yttrium-90.

[1]
b.ii.

The half-life of lutetium-177 is 6.75 days. Calculate the percentage remaining after 27 days.

[1]
b.iii.

Markscheme

more damaging than other radiation types
OR
very damaging to «cancer» cells
OR
high ionizing density «of alpha particles»

absorbed within a very short range of emission
OR
causes little damage to surrounding tissues

 

Accept “high ionizing power «of alpha particles»” for M1. 

Accept “low penetrating power «of alpha particles»” for M2.

[2 marks]

a.i.

«radioactive isotope/radionuclide/alpha-emitter» administered using carrier drug/protein/antibodies

[1 mark]

a.ii.

beta/β «radiation»

[1 mark]

b.i.

\({}_{39}^{90}Y \to {}_{40}^{90}Zr + \beta \)

 

Accept "\(_{ - 1}^{\;\,0}e/e/{e^ - }\)" OR "\(_{ - 1}^{\;\,0}\beta /{\beta ^ - }\)"

Accept ECF from (b) (i) if incorrect radiation identified, eg, \(_{39}^{90}Y \to _{37}^{86}Rb + _2^4He\)

[1 mark]

b.ii.

ALTERNATIVE 1:
«4 half-lives»
6.25 «%»

ALTERNATIVE 2:
«NtN0\({\left( {0.5} \right)^{\frac{t}{{{t_{1/2}}}}}} = 100{\left( {0.5} \right)^{\frac{{27}}{{6.75}}}} = \)» 6.25 «%»

[1 mark]

b.iii.

Examiners report

[N/A]
a.i.
[N/A]
a.ii.
[N/A]
b.i.
[N/A]
b.ii.
[N/A]
b.iii.

Syllabus sections

Options » D: Medicinal chemistry » D.8 Nuclear medicine (HL only)

View options