Date | May 2008 | Marks available | 3 | Reference code | 08M.1.sl.TZ1.10 |
Level | SL only | Paper | 1 | Time zone | TZ1 |
Command term | Calculate | Question number | 10 | Adapted from | N/A |
Question
Jane plans to travel from Amsterdam to Chicago. She changes \(1500\) Euros (\({\text{EUR}}\)) to US Dollars (\({\text{USD}}\)) at an exchange rate of \(1{\text{ EUR}}\) to \(1.33{\text{ USD}}\). Give all answers in this question correct to two decimal places.
Calculate the number of \({\text{USD}}\) Jane receives.
Jane spends \(1350{\text{ USD}}\) and then decides to convert the remainder back to \({\text{EUR}}\) at a rate of \(1{\text{ EUR}}\) to \(1.38{\text{ USD}}\).
Calculate the amount of \({\text{EUR}}\) Jane receives.
If Jane had waited until she returned to Amsterdam she could have changed her \({\text{USD}}\) at a rate of \(1{\text{ EUR}}\) to \(1.36{\text{ USD}}\) but the bank would have charged \(0.8\% \) commission.
Calculate the amount of \({\text{EUR}}\) Jane gained or lost by changing her money in Chicago.
Markscheme
Financial penalty (FP) may apply in this question.
\(1500 \times 1.33\)
(FP) \( = 1995.00\) (accept \(1995\)) (A1) (C1)
[1 mark]
Financial penalty (FP) may apply in this question.
\({\text{USD left}} = 1995 - 1350 = 645\) (A1)
\( = \frac{{645}}{{1.38}}{\text{ Euros}}\) (A1)(ft)
(FP) \( = 467.39{\text{ Euros}}\) (A1)(ft) (C3)
[3 marks]
Financial penalty (FP) may apply in this question.
\(\frac{{645}}{{1.36}} \times 0.992 = 470.47\) (A1)(ft)
(FP) She lost \(3.08{\text{ Euros}}\) (A1)(ft) (C2)
Notes: The word ‘lost’ is not required.
If candidate has divided in (a) and multiplied in (b) and (c) consistently award (A0)(A1)(ft)(A1)(ft) for answers of \( - 222.18\) for \({\text{USD}}\) left and \(306.61{\text{ Euros}}\) in (b) and (A1)(ft)(A1)(ft) for \(299.75\) and \(6.86\) in (c).
[2 marks]
Examiners report
This question was well answered by a number of the candidates although a significant number lost a mark due to a financial penalty through not giving an answer correct to 2 decimal places. A very common mistake was to use \(8\% \) (\(0.08\)) for \(0.8\% \) (\(0.008\)) as the multiplier in part (c).
This question was well answered by a number of the candidates although a significant number lost a mark due to a financial penalty through not giving an answer correct to 2 decimal places. A very common mistake was to use \(8\% \) (\(0.08\)) for \(0.8\% \) (\(0.008\)) as the multiplier in part (c).
This question was well answered by a number of the candidates although a significant number lost a mark due to a financial penalty through not giving an answer correct to 2 decimal places. A very common mistake was to use \(8\% \) (\(0.08\)) for \(0.8\% \) (\(0.008\)) as the multiplier in part (c).