| Date | May 2013 | Marks available | 2 | Reference code | 13M.1.sl.TZ1.11 |
| Level | SL only | Paper | 1 | Time zone | TZ1 |
| Command term | Calculate | Question number | 11 | Adapted from | N/A |
Question
Neung is going home to Vietnam after working in Singapore.
She has 5000 Singapore dollars (SGD) and changes these into American dollars (USD)
to take home.
The exchange rate between Singapore dollars (SGD) and American dollars (USD) is
1 USD = 1.2945 SGD.
There is also a 2.4 % commission on the exchange.
Calculate the amount of commission on the exchange in SGD.
Calculate the number of American dollars (USD) Neung takes home. Give your answer correct to 2 decimal places.
At the airport in Vietnam, Neung changes 150 USD into Vietnamese dong (VND) to pay for her transport home.
The exchange rate between American dollars (USD) and Vietnamese dong (VND) is
1 USD = 19 495 VND.
There is no commission.
Calculate the number of Vietnamese dong that Neung receives. Give your answer correct to the nearest thousand dong.
Markscheme
5000 × 0.024 (M1)
Note: Award (M1) for multiplication by 0.024.
=120 (A1) (C2)
\(4880 \times \frac{1}{{1.2945}}\) (M1)
Note: Award (M1) for multiplication by \(\frac{1}{{1.2945}}\).
= 3769.80 (A1)(ft) (C2)
Note: Correct answer to 2 dp only. Follow through from their part (a).
\(150 \times 19495\) (M1)
Note: Award (M1) for \( \times 19495\).
\(= 2924000\) (A1) (C2)
Notes: Correct answer to nearest 1000 only. Do not penalize incorrect accuracy in (c) if this has already been penalized in part (b).
Examiners report
Marks were awarded in part (a) for multiplication by 0.024 in part (b) for division by 1.2945 and in part (c) for multiplication by 19495. Candidates did not follow specified levels of accuracy. Candidates were able to answer later parts of the question even if they did not answer the first parts correctly.
Marks were awarded in part (a) for multiplication by 0.024 in part (b) for division by 1.2945 and in part (c) for multiplication by 19495. Candidates did not follow specified levels of accuracy. Candidates were able to answer later parts of the question even if they did not answer the first parts correctly.
Marks were awarded in part (a) for multiplication by 0.024 in part (b) for division by 1.2945 and in part (c) for multiplication by 19495. Candidates did not follow specified levels of accuracy. Candidates were able to answer later parts of the question even if they did not answer the first parts correctly.
