Date | May 2011 | Marks available | 2 | Reference code | 11M.1.sl.TZ2.12 |
Level | SL only | Paper | 1 | Time zone | TZ2 |
Command term | Calculate | Question number | 12 | Adapted from | N/A |
Question
A manufacturer in England makes \(16 000\) garden statues. \(12\% \) are defective and cannot be sold.
Find the number of statues that are non-defective.
The manufacturer sells each non-defective statue for \(5.25\) British pounds (GBP) to an American company. The exchange rate from GBP to US dollars (USD) is \(1{\text{ GBP}} = 1.6407{\text{ USD}}\).
Calculate the amount in USD paid by the American company for all the non-defective statues. Give your answer correct to two decimal places.
The American company sells one of the statues to an Australian customer for \(12{\text{ USD}}\). The exchange rate from Australian dollars (AUD) to USD is \(1{\text{ AUD}} = 0.8739{\text{ USD}}\) .
Calculate the amount that the Australian customer pays, in AUD, for this statue. Give your answer correct to two decimal places.
Markscheme
\(0.88 \times 16000\) OR \(16000 - 0.12 \times 16000\) (M1)
\(14080\) (A1) (C2)
[2 marks]
\(1.6407 \times 5.25 \times 14080\) (M1)
\(121 280.54{\text{ USD}}\) (A1)(ft) (C2)
Note: Follow through from their answer to part (a).
[2 marks]
\(12 \times \frac{1}{{0.8739}}\) (M1)
\(13.73{\text{ AUD}}\) (A1) (C2)
Note: If division used in part (b) and multiplication used in part (c), award (M0)(A0) for part (b) and (M1)(A1)(ft) for part (c).
[2 marks]
Examiners report
This question was generally well answered with much correct working seen in parts (a) and (b). The most popular incorrect answer in part (a) was \(1920\) – candidates simply stating the number of defective items rather than the number of non-defective items. Unfortunately in part (c) many candidates multiplied by \(0.8739\) rather than divided and \(10.49\) proved a popular, but erroneous, answer.
This question was generally well answered with much correct working seen in parts (a) and (b). The most popular incorrect answer in part (a) was \(1920\) – candidates simply stating the number of defective items rather than the number of non-defective items. Unfortunately in part (c) many candidates multiplied by \(0.8739\) rather than divided and \(10.49\) proved a popular, but erroneous, answer.
This question was generally well answered with much correct working seen in parts (a) and (b). The most popular incorrect answer in part (a) was \(1920\) – candidates simply stating the number of defective items rather than the number of non-defective items. Unfortunately in part (c) many candidates multiplied by \(0.8739\) rather than divided and \(10.49\) proved a popular, but erroneous, answer.