Date | May 2022 | Marks available | 2 | Reference code | 22M.1.AHL.TZ2.8 |
Level | Additional Higher Level | Paper | Paper 1 | Time zone | Time zone 2 |
Command term | Calculate | Question number | 8 | Adapted from | N/A |
Question
The diagram shows a sector, OABOAB, of a circle with centre OO and radius rr, such that AÔB=θAÔB=θ.
Sam measured the value of rr to be 2 cm2cm and the value of θθ to be 30°30°.
It is found that Sam’s measurements are accurate to only one significant figure.
Use Sam’s measurements to calculate the area of the sector. Give your answer to four significant figures.
Find the upper bound and lower bound of the area of the sector.
Find, with justification, the largest possible percentage error if the answer to part (a) is recorded as the area of the sector.
Markscheme
π×22×30360π×22×30360 (M1)
=1.047 cm2=1.047cm2 A1
Note: Do not award the final mark if the answer is not correct to 4 sf.
[2 marks]
attempt to substitute any two values from 1.5, 2.5, 251.5, 2.5, 25 or 3535 into area of sector formula (M1)
(upper bound=π×2.52×35360=) 1.91 cm2 (1.90895…)(upper bound=π×2.52×35360=) 1.91cm2 (1.90895…) A1
(lower bound=π×1.52×25360=) 0.491 cm2 (0.490873…)(lower bound=π×1.52×25360=) 0.491cm2 (0.490873…) A1
Note: Given the nature of the question, accept correctly rounded OR correctly truncated 33 significant figure answers.
[3 marks]
(|1.047-1.90895…1.90895…|×100=) 45.2 (%) (45.1532…)(∣∣1.047−1.90895…1.90895…∣∣×100=) 45.2 (%) (45.1532…) A1
(|1.047-0.490873…0.490873…|×100=) 113 (%) (113.293…)(∣∣1.047−0.490873…0.490873…∣∣×100=) 113 (%) (113.293…) A1
so the largest percentage error is 113 %113% A1
Note: Accept 45.1 (%)45.1 (%) (45.142845.1428), from use of full accuracy answers. Given the nature of the question, accept correctly rounded OR correctly truncated 33 significant figure answers. Award A0A1A0 if 113%113% is the only value found.
[3 marks]
Examiners report
In part (a), the area was almost always found correctly although some candidates gave the answer 1.0472 which is correct to 4 decimal places, not 4 significant figures as required. In part (b), many candidates failed to realize that the upper bounds for r and θ were 2.5 and 35° and lower bounds were 1.5 and 25°. Consequently, the bounds for the area were incorrect. In many cases, the incorrect values in part (b) were followed through into part (c) although in the percentage error calculations, many candidates had 1.047 in the denominator instead of the appropriate bound.