Date | May 2022 | Marks available | 5 | Reference code | 22M.1.SL.TZ1.4 |
Level | Standard Level | Paper | Paper 1 | Time zone | Time zone 1 |
Command term | Find | Question number | 4 | Adapted from | N/A |
Question
Three towns, A, B and C are represented as coordinates on a map, where the x and y axes represent the distances east and north of an origin, respectively, measured in kilometres.
Town A is located at (−6, −1) and town B is located at (8, 6). A road runs along the perpendicular bisector of [AB]. This information is shown in the following diagram.
Find the equation of the line that the road follows.
Town C is due north of town A and the road passes through town C.
Find the y-coordinate of town C.
Markscheme
midpoint (1, 2.5) A1
mAB=6-(-1)8-(-6)=12 (M1)A1
Note: Accept equivalent gradient statements including using midpoint.
m⊥=-2 M1
Note: Award M1 for finding the negative reciprocal of their gradient.
y-2.5=-2(x-1) OR y=-2x+92 OR 4x+2y-9=0 A1
[5 marks]
substituting x=-6 into their equation from part (a) (M1)
y=-2(-6)+92
y=16.5 A1
Note: Award M1A0 for (-6, 16.5) as their final answer.
[2 marks]
Examiners report
A large proportion of candidates seemed to be well drilled into finding the gradient of a line and the subsequent gradient of the normal. But without finding the coordinates of the midpoint of AB, no more marks were gained.
Many candidates worked out the value of y correctly (or “correct” following the value they found in part (a)) but then incorrectly gave their answer as a coordinate pair.