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Date May 2018 Marks available 6 Reference code 18M.1.SL.TZ2.S_7
Level Standard Level Paper Paper 1 Time zone Time zone 2
Command term Find Question number S_7 Adapted from N/A

Question

An arithmetic sequence has  u 1 = lo g c ( p ) and u 2 = lo g c ( p q ) , where  c > 1 and p , q > 0 .

Let  p = c 2 and  q = c 3 . Find the value of n = 1 20 u n .

Markscheme

METHOD 1 (finding  u 1 and d)

recognizing  = S 20  (seen anywhere)      (A1)

attempt to find  u 1 or d using  lo g c c k = k      (M1)
eg   lo g c c 3 lo g c c , correct value of  u 1 or d

u 1 = 2, d = 3 (seen anywhere)      (A1)(A1)

correct working     (A1)
eg   S 20 = 20 2 ( 2 × 2 + 19 × 3 ) , S 20 = 20 2 ( 2 + 59 ) , 10 ( 61 )

n = 1 20 u n = 610     A1 N2

 

METHOD 2 (expressing S in terms of c)

recognizing  = S 20  (seen anywhere)      (A1)

correct expression for S in terms of c      (A1)
eg   10 ( 2 lo g c c 2 + 19 lo g c c 3 )

lo g c c 2 = 2 , lo g c c 3 = 3   (seen anywhere)     (A1)(A1)

correct working      (A1)

eg   S 20 = 20 2 ( 2 × 2 + 19 × 3 ) , S 20 = 20 2 ( 2 + 59 ) , 10 ( 61 )

n = 1 20 u n = 610     A1 N2

 

METHOD 3 (expressing S in terms of c)

recognizing  = S 20  (seen anywhere)      (A1)

correct expression for S in terms of c      (A1)
eg   10 ( 2 lo g c c 2 + 19 lo g c c 3 )

correct application of log law     (A1)
eg   2 lo g c c 2 = lo g c c 4 , 19 lo g c c 3 = lo g c c 57 , 10 ( lo g c ( c 2 ) 2 + lo g c ( c 3 ) 19 ) , 10 ( lo g c c 4 + lo g c c 57 ) , 10 ( lo g c c 61 )

correct application of definition of log      (A1)
eg   lo g c c 61 = 61 , lo g c c 4 = 4 , lo g c c 57 = 57

correct working     (A1)
eg   S 20 = 20 2 ( 4 + 57 ) , 10 ( 61 )

n = 1 20 u n = 610     A1 N2

[6 marks]

 

Examiners report

[N/A]

Syllabus sections

Topic 1—Number and algebra » SL 1.2—Arithmetic sequences and series
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