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Date May 2017 Marks available 1 Reference code 17M.1.AHL.TZ2.H_3
Level Additional Higher Level Paper Paper 1 Time zone Time zone 2
Command term Find Question number H_3 Adapted from N/A

Question

The 1st, 4th and 8th terms of an arithmetic sequence, with common difference dd, d0d0, are the first three terms of a geometric sequence, with common ratio rr. Given that the 1st term of both sequences is 9 find

the value of dd;

[4]
a.

the value of rr;

[1]
b.

Markscheme

* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.

EITHER

the first three terms of the geometric sequence are 99, 9r9r and 9r29r2     (M1)

9+3d=9r(3+d=3r)9+3d=9r(3+d=3r) and 9+7d=9r29+7d=9r2     (A1)

attempt to solve simultaneously     (M1)

9+7d=9(3+d3)29+7d=9(3+d3)2

OR

the 1st1st, 4th4th and 8th8th terms of the arithmetic sequence are

9, 9+3d, 9+7d9, 9+3d, 9+7d     (M1)

9+7d9+3d=9+3d99+7d9+3d=9+3d9     (A1)

attempt to solve     (M1)

THEN

d=1d=1     A1

[4 marks]

a.

r=43r=43     A1

 

Note:     Accept answers where a candidate obtains dd by finding rr first. The first two marks in either method for part (a) are awarded for the same ideas and the third mark is awarded for attempting to solve an equation in rr.

 

[1 mark]

b.

Examiners report

[N/A]
a.
[N/A]
b.

Syllabus sections

Topic 1—Number and algebra » SL 1.2—Arithmetic sequences and series
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Topic 1—Number and algebra

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