Date | May 2021 | Marks available | 3 | Reference code | 21M.1.SL.TZ2.5 |
Level | Standard Level | Paper | Paper 1 (without calculator) | Time zone | Time zone 2 |
Command term | Find | Question number | 5 | Adapted from | N/A |
Question
Consider the function f defined by f(x)=ln(x2-16) for x>4.
The following diagram shows part of the graph of f which crosses the x-axis at point A, with coordinates (a, 0). The line L is the tangent to the graph of f at the point B.
Find the exact value of a.
Given that the gradient of L is 13, find the x-coordinate of B.
Markscheme
ln(x2-16)=0 (M1)
e0=x2-16(=1)
x2=17 OR x=±√17 (A1)
a=√17 A1
[3 marks]
attempt to differentiate (must include 2x and/or 1x2-16) (M1)
f'(x)=2xx2-16 A1
setting their derivative =13 M1
2xx2-16=13
x2-16=6x OR x2-6x-16=0 (or equivalent) A1
valid attempt to solve their quadratic (M1)
x=8 A1
Note: Award A0 if the candidate’s final answer includes additional solutions (such as x=−2, 8).
[6 marks]