Date | May 2017 | Marks available | 2 | Reference code | 17M.1.SL.TZ1.T_9 |
Level | Standard Level | Paper | Paper 1 (with calculator from previous syllabus) | Time zone | Time zone 1 |
Command term | Find | Question number | T_9 | Adapted from | N/A |
Question
A type of candy is packaged in a right circular cone that has volume 100 cm3 and vertical height 8 cm.
Find the radius, r, of the circular base of the cone.
Find the slant height, l, of the cone.
Find the curved surface area of the cone.
Markscheme
* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.
100=13πr2(8) (M1)
Note: Award (M1) for correct substitution into volume of cone formula.
r=3.45 (cm) (3.45494… (cm)) (A1) (C2)
[2 marks]
l2=82+(3.45494…)2 (M1)
Note: Award (M1) for correct substitution into Pythagoras’ theorem.
l=8.71 (cm) (8.71416… (cm)) (A1)(ft) (C2)
Note: Follow through from part (a).
[2 marks]
π×3.45494…×8.71416… (M1)
Note: Award (M1) for their correct substitutions into curved surface area of a cone formula.
=94.6 cm2 (94.5836… cm2) (A1)(ft) (C2)
Note: Follow through from parts (a) and (b). Accept 94.4 cm2 from use of 3 sf values.
[2 marks]