Date | November 2020 | Marks available | 1 | Reference code | 20N.3.SL.TZ0.1 |
Level | Standard level | Paper | Paper 3 | Time zone | 0 - no time zone |
Command term | Identify | Question number | 1 | Adapted from | N/A |
Question
A spherical soap bubble is made of a thin film of soapy water. The bubble has an internal air pressure PiPi and is formed in air of constant pressure PoPo. The theoretical prediction for the variation of (Pi-Po)(Pi−Po) is given by the equation
(Pi-Po)=4gR(Pi−Po)=4gR
where γγ is a constant for the thin film and RR is the radius of the bubble.
Data for (Pi-Po)(Pi−Po) and RR were collected under controlled conditions and plotted as a graph showing the variation of (Pi-Po)(Pi−Po) with 1R1R.
Suggest whether the data are consistent with the theoretical prediction.
Show that the value of γγ is about 0.03.
Identify the fundamental units of γγ.
In order to find the uncertainty for γγ, a maximum gradient line would be drawn. On the graph, sketch the maximum gradient line for the data.
The percentage uncertainty for γγ is 15%15%. State γγ, with its absolute uncertainty.
The expected value of γγ is 0.0270.027. Comment on your result.
Markscheme
«theory suggests» Pi-PoPi−Po is proportional to 1R1R ✓
graph/line of best fit is straight/linear «so yes»
OR
graph/line of best fit passes through the origin «so yes» ✓
MP1: Accept ‘linear’
MP2 do not award if there is any contradiction
eg: graph not proportional, does not pass through origin.
gradient == «4γ4γ» =0.10=0.10
OR
use of equation with coordinates of a point ✓
γ=0.025γ=0.025 ✓
MP1 allow gradients in range 0.0980.098 to 0.1020.102
MP2 allow a range 0.0240.024 to 0.0260.026 for γγ
kg s-2kgs−2 ✓
Accept kgs2kgs2
straight line, gradient greater than line of best fit, and within the error bars ✓
«15%15% of 0.0250.025» = 0.003750.00375
OR
«15%15% of 0.0300.030» = 0.00450.0045 ✓
rounds uncertainty to 1sf
±0.004±0.004
OR
±0.005±0.005 ✓
Allow ECF from (b)(i)
Award [2] marks for a bald correct answer
Experimental value matches this/correct, as expected value within the range ✓
OR
experimental value does not match/incorrect, as it is not within range ✓
Examiners report
Many students obtained full marks here although a significant number did not acknowledge that the graph was through the origin and lost a mark.
Very well answered either by obtaining the gradient or replacing with the coordinates of a point.
Although the question was specifically about the fundamental units, several candidates lost the mark by answering Pa m.
Almost all candidates were able to draw the correct maximum gradient line.
Well answered. A significant number did not round the uncertainty to match the value of gamma.