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Date	November 2018	Marks available	1	Reference code	18N.3.HL.TZ0.6
Level	Higher level	Paper	Paper 3	Time zone	0 - no time zone
Command term	Show that	Question number	6	Adapted from	N/A

Question

An electron with total energy 1.50 MeV collides with a positron at rest. As a result two photons are produced. One photon moves in the same direction as the electron and the other in the opposite direction.

The momenta of the photons produced have magnitudes p₁ and p₂. A student writes the following correct equations.

p₁ – p₂ = 1.41 MeV c^–1

p₁ + p₂ = 2.01 MeV c^–1

Show that the momentum of the electron is 1.41 MeV c^–1.

[1]

a.

Explain the origin of each equation.

[2]

b.i.

Calculate, in MeV c^–1, p₁ and p₂.

[2]

b.ii.

Markscheme

$pc = \sqrt {{E^2} - {{\left( {m{c^2}} \right)}^2}} = \sqrt {{{150}^2} - {{0.511}^2}}$ «= 1.410 MeV» ✔

a.

first equation is due to momentum conservation ✔

second equation is due to total energy conservation ✔

b.i.

adding 2p₁ = 3.42 MeV c^–1 ⇒ p₁ = 1.17 MeV c^–1 ✔

p₂ = 0.30 MeV c^–1 ✔

b.ii.

Examiners report

[N/A]

a.

[N/A]

b.i.

[N/A]

b.ii.

Syllabus sections

Option A: Relativity » Option A: Relativity (Additional higher level option topics) » A.4 – Relativistic mechanics (HL only)

Show 27 related questions

18M.3.HL.TZ1.6b:
State the rest mass of the pion with an appropriate unit.
18M.3.HL.TZ2.6b.ii:
The diagram shows the paths of the incident protons together with the proton and neutron created in the interaction. On the diagram, draw the path of the pion.
18M.3.HL.TZ2.6a:
Calculate the gamma (γ) factor for one of the protons.
18N.3.HL.TZ0.6b.i: Explain the origin of each equation.
18N.3.HL.TZ0.6b.ii: Calculate, in MeV c–1, p1 and p2.
19M.3.HL.TZ2.8bi: Determine the momentum of the proton.
16N.3.HL.TZ0.8a: Explain, in terms of a conservation law, why two photons need to be created.
17N.3.HL.TZ0.7b:
Determine, using your answer to (a), the initial speed of the ${\Lambda ^0}$ particle.
16N.3.HL.TZ0.8b:
Determine the speed of the incoming electron.
16N.3.HL.TZ0.8c:
Calculate the energy and the momentum for each photon after the collision.
17M.3.HL.TZ1.5a:
Calculate the potential difference V.
19M.3.HL.TZ2.8bii:
Determine the speed of the proton.
18M.3.HL.TZ2.6b.i:
Determine, in terms of MeV c^–1, the momentum of the pion.
19M.3.HL.TZ1.6a:
Show that energy is conserved in this decay.
19N.3.HL.TZ0.5a(i):
the total energy.
19N.3.HL.TZ0.5a(ii):
the speed.
17N.3.HL.TZ0.7a:
Determine the rest mass of the ${\Lambda ^0}$ particle.
19N.3.HL.TZ0.5b:
Determine the rest mass of X.
20N.3.HL.TZ0.6c: In relativistic reactions the mass of the products may be less than the mass of the...
20N.3.HL.TZ0.6a: Define rest mass.
17M.3.HL.TZ2.6:
A lambda $\Lambda$ ⁰ particle at rest decays into a proton p and a pion ${\pi ^ - }$ according to the reaction

$\Lambda$ ⁰ → p + $\pi$ ^–

where the rest energy of p = 938 MeV and the rest energy of $\pi$ ^– = 140 MeV.

The speed of the pion after the decay is 0.579c. For this speed $\gamma$ = 1.2265. Calculate the speed of the proton.
18M.3.HL.TZ1.6a.ii:
show that the energy of the pion is about 140 MeV.
20N.3.HL.TZ0.6b:
Calculate the total energy of the deuterium particle in $MeV$ .
19M.3.HL.TZ2.8a: Define total energy.
19M.3.HL.TZ2.8biii:
Calculate the potential difference V.
17M.3.HL.TZ1.5b:
The proton collides with an antiproton moving with the same speed in the opposite direction. As a result both particles are annihilated and two photons of equal energy are produced.

Determine the momentum of one of the photons.
19M.3.HL.TZ1.6b:
Calculate the speed of the pion.

Hide related questions

Option A: Relativity » Option A: Relativity (Additional higher level option topics)

Option A: Relativity