Date | May 2018 | Marks available | 2 | Reference code | 18M.3.SL.TZ2.5 |
Level | Standard level | Paper | Paper 3 | Time zone | 2 |
Command term | Determine | Question number | 5 | Adapted from | N/A |
Question
Observer A detects the creation (event 1) and decay (event 2) of a nuclear particle. After creation, the particle moves at a constant speed relative to A. As measured by A, the distance between the events is 15 m and the time between the events is 9.0 × 10–8 s.
Observer B moves with the particle.
For event 1 and event 2,
Explain what is meant by the statement that the spacetime interval is an invariant quantity.
calculate the spacetime interval.
determine the time between them according to observer B.
Outline why the observed times are different for A and B.
Markscheme
quantity that is the same/constant in all inertial frames
[1 mark]
spacetime interval = 272 – 152 = 504 «m2»
[1 mark]
ALTERNATIVE 1
Evidence of x′ = 0
t′ «» = 7.5 × 10–8 «s»
ALTERNATIVE 2
γ = 1.2
t′ «= » = 7.5 × 10–8 «s»
[2 marks]
observer B measures the proper time and this is the shortest time measured
OR
time dilation occurs «for B's journey» according to A
OR
observer B is stationary relative to the particle, observer A is not
[1 mark]