ibo.org
Updates to Questionbank

User interface language: English | Español

« Back to questions in DP Chemistry

Date November 2020 Marks available 1 Reference code 20N.2.hl.TZ0.1
Level HL Paper 2 Time zone TZ0
Command term Justify and Predict Question number 1 Adapted from N/A

Question

Chlorine undergoes many reactions.

2.67 g of manganese(IV) oxide was added to 200.0 cm3 of 2.00 mol dm-3 HCl.

MnO2 (s)+4HCl (aq)→Cl2 (g)+2H2O (l)+MnCl2 (aq)

Chlorine gas reacts with water to produce hypochlorous acid and hydrochloric acid.

Cl2 (g)+H2O (l)⇌HClO (aq)+HCl (aq)

CCl2F2 is a common chlorofluorocarbon, CFC.

State the full electron configuration of the chlorine atom.

[1]
a(i).

State, giving a reason, whether the chlorine atom or the chloride ion has a larger radius.

[1]
a(ii).

Outline why the chlorine atom has a smaller atomic radius than the sulfur atom.

[2]
a(iii).

The mass spectrum of chlorine is shown.

NIST Mass Spectrometry Data Center Collection © 2014 copyright by the U.S. Secretary of Commerce on behalf of the United States of America. All rights reserved.


Outline the reason for the two peaks at m/z=35 and 37.

[1]
a(iv).

Explain the presence and relative abundance of the peak at m/z=74.

[2]
a(v).

Calculate the amount, in mol, of manganese(IV) oxide added.

[1]
b(i).

Determine the limiting reactant, showing your calculations.

[2]
b(ii).

Determine the excess amount, in mol, of the other reactant.

[1]
b(iii).

Calculate the volume of chlorine, in dm3, produced if the reaction is conducted at standard temperature and pressure (STP). Use section 2 of the data booklet.

[1]
b(iv).

State the oxidation state of manganese in MnO2 and MnCl2.

[2]
b(v).

Deduce, referring to oxidation states, whether MnO2 is an oxidizing or reducing agent.

[1]
b(vi).

Hypochlorous acid is considered a weak acid. Outline what is meant by the term weak acid.

 

[1]
c(i).

State the formula of the conjugate base of hypochlorous acid.

[1]
c(ii).

Calculate the concentration of H+ (aq) in a HClO aq solution with a pH=3.61.

[1]
c(iii).

State the type of reaction occurring when ethane reacts with chlorine to produce chloroethane.

[1]
d(i).

Predict, giving a reason, whether ethane or chloroethane is more reactive.

[1]
d(ii).

Explain the mechanism of the reaction between chloroethane and aqueous sodium hydroxide, NaOH (aq), using curly arrows to represent the movement of electron pairs.

[3]
d(iii).

Ethoxyethane (diethyl ether) can be used as a solvent for this conversion.
Draw the structural formula of ethoxyethane

[1]
d(iv).

Deduce the number of signals and chemical shifts with splitting patterns in the 1H NMR spectrum of ethoxyethane. Use section 27 of the data booklet.

[3]
d(v).

Calculate the percentage by mass of chlorine in CCl2F2.

[2]
e(i).

Comment on how international cooperation has contributed to the lowering of CFC emissions responsible for ozone depletion.

[1]
e(ii).

CFCs produce chlorine radicals. Write two successive propagation steps to show how chlorine radicals catalyse the depletion of ozone.

[2]
e(iii).

Markscheme

1s22s22p63s23p5 ✔


Do not accept condensed electron configuration.

a(i).

Cl- AND more «electron–electron» repulsion ✔


Accept Cl- AND has an extra electron.

a(ii).

Cl has a greater nuclear charge/number of protons/Zeff «causing a stronger pull on the outer electrons» ✔

same number of shells
OR
same «outer» energy level
OR
similar shielding ✔

a(iii).

«two major» isotopes «of atomic mass 35 and 37» ✔

a(iv).

«diatomic» molecule composed of «two» chlorine-37 atoms ✔

chlorine-37 is the least abundant «isotope»
OR
low probability of two Cl37 «isotopes» occurring in a molecule ✔

a(v).

«2.67 g86.94 g mol-1=»0.0307 «mol» ✔

b(i).

«nHCl=2.00 mol dm-3×0.2000 dm3»=0.400 mol ✔

«0.4004=» 0.100 mol AND MnO2 is the limiting reactant ✔


Accept other valid methods of determining the limiting reactant in M2.

b(ii).

«0.0307 mol×4=0.123 mol»

«0.400 mol–0.123 mol=»0.277 «mol» ✔

b(iii).

«0.0307 mol×22.7 dm3 mol−1=» 0.697 «dm3» ✔


Accept methods employing pV=nRT.

b(iv).

MnO2: +4 ✔

MnCl2: +2 ✔

b(v).

oxidizing agent AND oxidation state of Mn changes from +4 to +2/decreases ✔

b(vi).

partially dissociates/ionizes «in water» ✔

c(i).

ClO- ✔

c(ii).

«[H+]=10−3.61=» 2.5×10−4 «mol dm−3» ✔

c(iii).

«free radical» substitution/SR ✔


Do not accept electrophilic or nucleophilic substitution.

d(i).

chloroethane AND C–Cl bond is weaker/324 kJ mol−1 than C–H bond/414 kJ mol−1
OR
chloroethane AND contains a polar bond ✔


Accept “chloroethane AND polar”.

d(ii).

curly arrow going from lone pair/negative charge on O in −OH to C ✔

curly arrow showing Cl leaving ✔

representation of transition state showing negative charge, square brackets and partial bonds ✔

 

Accept OH- with or without the lone pair.

Do not accept curly arrows originating on H in OH-.

Accept curly arrows in the transition state.

Do not penalize if HO and Cl are not at 180°.

Do not award M3 if OH-C bond is represented. 

d(iii).

 / CH3CH2OCH2CH3 ✔


Accept (CH3CH2)2O.

d(iv).

2 «signals» ✔

0.9−1.0 AND triplet ✔

3.3−3.7 AND quartet ✔

Accept any values in the ranges.

Award [1] for two correct chemical shifts or two correct splitting patterns.

d(v).

«M(CCl2F2) =» 120.91 «g mol−1»  ✔

2×35.45 g mol-1120.91 g mol-1×100%=» 58.64 «%» ✔


Award [2] for correct final answer.

e(i).

Any of:

research «collaboration» for alternative technologies «to replace CFCs»
OR
technologies «developed»/data could be shared
OR
political pressure/Montreal Protocol/governments passing legislations ✔

 

Do not accept just “collaboration”.

Do not accept any reference to CFC as greenhouse gas or product of fossil fuel combustion.

Accept reference to specific measures, such as agreement on banning use/manufacture of CFCs.

e(ii).

O3+Cl·→O2+ClO· ✔

ClO·+O·→O2+Cl·
OR
ClO·+O3→Cl·+2O2 ✔

Penalize missing/incorrect radical dot (∙) once only.

e(iii).

Examiners report

Well answered question with 90% of candidates correctly identifying the complete electron configuration for chlorine.

a(i).

Most candidates could correctly explain the relative sizes of chlorine atom and chloride ion.

a(ii).

Fairly well answered though some candidates missed M2 for not recognizing the same number of shells affected.

a(iii).

More than 80% could identify that the two peaks in the MS of chlorine are due to different isotopes.

a(iv).

Not well answered. Some candidates were able to identify m/z 74 being due to the m/z of two Cl-37 atoms, however fewer candidates were able to explain the relative abundance of the isotope.

a(v).

Stoichiometric calculations were generally well done and over 90% could calculate mol from a given mass.

b(i).

90% of candidates earned full marks on this 2-mark question involving finding a limiting reactant.

b(ii).

Surprisingly, quite a number of candidates struggled with the quantity of excess reactant despite correctly identifying limiting reactant previously.

b(iii).

Most candidates could find the volume of gas produced in a reaction under standard conditions.

b(iv).

More than 90% could identify the oxidation number of manganese in both MnO2 and MnCl2.

b(v).

Most candidates stated that MnO2 is an oxidizing agent in the reaction but many did not get the mark because there was no reference to oxidation states.

b(vi).

Another well answered 1-mark question where candidates correctly identified a weak acid as an acid which partially dissociates in water. 

c(i).

Roughly ⅓ of the candidates failed to identify the conjugate base, perhaps distracted by the fact it was not contained in the equation given.

c(ii).

Vast majority of candidates could calculate the concentration of H+ (aq) in a HClO (aq) solution with a pH =3.61.

c(iii).

Many identified the reaction of chlorine with ethane as free-radical substitution, or just substitution, with some erroneously stating nucleophilic or electrophilic substitution.

d(i).

The underlying reasons for the relative reactivity of ethane and chloroethane were not very well known with a few giving erroneous reasons and some stating ethane more reactive.

d(ii).

Few earned full marks for the curly arrow mechanism of the reaction between sodium hydroxide and chloroethane. Mistakes being careless curly arrow drawing, inappropriate –OH notation, curly arrows from the hydrogen or from the carbon to the C–Cl bond, or a method that missed the transition state.

d(iii).

Approximately 60% could draw ethoxyethane however many demonstrated little knowledge of structure of an ether molecule.

d(iv).

A poorly answered question with some getting full marks on this 1HNMR spectrum of ethoxyethane question. Very few could identify all 3 of number of signals, chemical shift, and splitting pattern.

d(v).

Another good example of candidates being well rehearsed in calculations with 90% earning 2/2 on this question of calculation percentage by mass composition. 

e(i).

Somewhat disappointing answers on this question about how international cooperation has contributed to the lowering of CFC emissions. Many gave vague answers and some referred to carbon emissions and global warming.

e(ii).

Few could construct the propagation equations showing how CFCs affect ozone, and many lost marks by failing to identify ClO· as a radical.

e(iii).

Syllabus sections

Core » Topic 10: Organic chemistry » 10.2 Functional group chemistry
Show 137 related questions
Hide related questions
Core » Topic 10: Organic chemistry
Core

View options

© International Baccalaureate Organization 2023
International Baccalaureate® - Baccalauréat International® - Bachillerato Internacional®
Terms and conditions | Privacy policy