Date | May 2009 | Marks available | 5 | Reference code | 09M.2.hl.TZ2.5 |
Level | HL only | Paper | 2 | Time zone | TZ2 |
Command term | Find | Question number | 5 | Adapted from | N/A |
Question
(a) Find the percentage of the population that has been vaccinated.
(b) A randomly chosen person catches the virus. Find the probability that this person has been vaccinated.
Markscheme
(a)
using the law of total probabilities: (M1)
\(0.1p + 0.3\left( {1 - p} \right) = 0.22\) A1
\(0.1p + 0.3 - 0.3p = 0.22\)
\(0.2p = 0.88\)
\(p = \frac{{0.88}}{{0.2}} = 0.4\)
\(p = 40\% \) (accept \(0.4\)) A1
(b) required probability \( = \frac{{0.4 \times 0.1}}{{0.22}}\) M1
\( = \frac{2}{{11}}\) (\(0.182\)) A1
[5 marks]
Examiners report
Most candidates who successfully answered this question had first drawn a tree diagram, using a symbol to denote the probability that a randomly chosen person had received the influenza virus. For those who did not draw a tree diagram, there was poor understanding of how to apply the conditional probability formula.