Date | May 2008 | Marks available | 6 | Reference code | 08M.2.hl.TZ1.8 |
Level | HL only | Paper | 2 | Time zone | TZ1 |
Command term | Find | Question number | 8 | Adapted from | N/A |
Question
Only two international airlines fly daily into an airport. UN Air has 70 flights a day and IS Air has 65 flights a day. Passengers flying with UN Air have an 18 % probability of losing their luggage and passengers flying with IS Air have a 23 % probability of losing their luggage. You overhear someone in the airport complain about her luggage being lost.
Find the probability that she travelled with IS Air.
Markscheme
METHOD 1
(M1)
Let P(I) be the probability of flying IS Air, P(U) be the probability flying UN Air and P(L) be the probability of luggage lost.
\({\text{P}}(I|L) = \frac{{{\text{P}}(I \cap L)}}{{{\text{P}}(L)}}{\text{ }}\left( {{\text{or Bayes' formula , P}}(I|L) = \frac{{{\text{P}}(L|I){\text{P}}(I)}}{{{\text{P}}(L|I){\text{P}}(I) + {\text{P}}(L|U){\text{P}}(U)}}} \right)\) (M1)
\( = \frac{{0.23 \times \frac{{65}}{{135}}}}{{0.18 \times \frac{{70}}{{135}} + 0.23 \times \frac{{65}}{{135}}}}\) A1A1A1
\( = \frac{{299}}{{551}}{\text{ }}( = 0.543,{\text{ accept }}0.542)\) A1
[6 marks]
METHOD 2
Expected number of suitcases lost by UN Air is \(0.18 \times 70 = 12.6\) M1A1
Expected number of suitcases lost by IS Air is \(0.23 \times 65 = 14.95\) A1
\({\text{P}}(I|L) = \frac{{14.95}}{{12.6 + 14.95}}\) M1A1
\( = 0.543\) A1
[6 marks]
Examiners report
This question was well answered by the majority of candidates. Most candidates used either tree diagrams or expected value methods.