Date | May 2016 | Marks available | 2 | Reference code | 16M.2.SL.TZ0.7 |
Level | Standard level | Paper | Paper 2 | Time zone | Time zone 0 |
Command term | Deduce | Question number | 7 | Adapted from | N/A |
Question
The Sun has a radius of 7.0×108m and is a distance 1.5×1011 m from Earth. The surface temperature of the Sun is 5800 K.
Show that the intensity of the solar radiation incident on the upper atmosphere of the Earth is approximately 1400Wm−2.
The albedo of the atmosphere is 0.30. Deduce that the average intensity over the entire surface of the Earth is 245Wm−2.
Estimate the average surface temperature of the Earth.
Markscheme
\(I = \frac{{\sigma A{T^4}}}{{4\pi {d^2}}}\)
\( = \frac{{5.67 \times {{10}^{ - 8}} \times {{\left( {7.0 \times {{10}^8}} \right)}^2} \times {{5800}^4}}}{{{{\left( {1.5 \times {{10}^{11}}} \right)}^2}}}\)
OR \( \frac{{5.67 \times {{10}^{ - 8}} \times 4\pi \times {{\left( {7.0 \times {{10}^8}} \right)}^2} \times {{5800}^4}}}{{4\pi \times {{\left( {1.5 \times {{10}^{11}}} \right)}^2}}}\)
I=1397 Wm−2
In this question we must see 4SF to award MP3.
Allow candidate to add radius of Sun to Earth–Sun distance. Yields 1386 Wm–2.
«transmitted intensity =» 0.70 × 1400 «= 980Wm–2»
\(\frac{{\pi {R^2}}}{{4\pi {R^2}}} \times 980{\rm{W}}{{\rm{m}}^{ - 2}}\)
245Wm–2
5.67 × 10–8 × T4 = 245
T = 256K