Date | May 2014 | Marks available | 12 | Reference code | 14M.1.hl.TZ0.8 |
Level | HL only | Paper | 1 | Time zone | TZ0 |
Command term | Find and Show that | Question number | 8 | Adapted from | N/A |
Question
The group {G, ∗} has a subgroup {H, ∗}. The relation R is defined, for x, y∈G, by xRy if and only if x−1∗y∈H.
(a) Show that R is an equivalence relation.
(b) Given that G={0, ±1, ±2, …}, H={0, ±4, ±8, …} and ∗ denotes addition, find the equivalence class containing the number 3.
Markscheme
(a) reflexive_
x−1x=e∈H A1
therefore xRx and R is reflexive R1
symmetric_
Note: Accept the word commutative.
let xRy so that x−1y∈H M1
the inverse of x−1y is y−1x∈H A1
therefore yRx and R is symmetric R1
transitive_
let xRy and yRz so x−1y∈H and y−1z∈H M1
therefore x−1yy−1z=x−1z∈H A1
therefore xRz and R is transitive R1
hence R is an equivalence relation AG
[8 marks]
(b) the identity is 0 so the inverse of 3 is −3 (R1)
the equivalence class of 3 contains x where −3+x∈H (M1)
−3+x=4n (n∈Z) (M1)
x=3+4n (n∈Z) A1
Note: Accept {…−5, −1, 3, 7, …} or x≡3(mod.
Note: If no other relevant working seen award A3 for \{ 3 + 4n\} or \{ \ldots - 5,{\text{ }} - 1,{\text{ }}3,{\text{ }}7,{\text{ }} \ldots \} seen anywhere.
[4 marks]