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Date May 2008 Marks available 3 Reference code 08M.1.sl.TZ2.8
Level SL only Paper 1 Time zone TZ2
Command term Find Question number 8 Adapted from N/A

Question

Emma places \({\text{€}}8000\) in a bank account that pays a nominal interest rate of \(5\% \) per annum, compounded quarterly.

Calculate the amount of money that Emma would have in her account after 15 years. Give your answer correct to the nearest Euro.

[3]
a.

After a period of time she decides to withdraw the money from this bank. There is \({\text{€}}9058.17\) in her account. Find the number of months that Emma had left her money in the account.

[3]
b.

Markscheme

\(FV = 8000{(1.0125)^{60}}\)     (M1)(A1)

Note: (M1) for substituting in compound interest formula, (A1) for correct substitution.

\({\text{€}}16857\) only     (A1)     (C3)

[3 marks]

a.

\(8000{(1.0125)^n} = 9058.17\)     (M1)


Note: (M1) for equating compound interest formula to \(9058.17\)


\(n = 10\) correct answer only     (A1)


So 30 months, (ft) on their \(n\)      (A1)(ft)     (C3)


Note: Award (C2) for \(2.5\) seen with no working.

[3 marks]

b.

Examiners report

Again this is a question that has been tested before but few candidates managed to gain full marks. Many, in part (b), believed they had to subtract \(8000\) from the value to get the interest first. This could possibly be a result of the way the formula is given in the formula booklet so teachers need to be aware of this.

a.

Again this is a question that has been tested before but few candidates managed to gain full marks. Many, in part (b), believed they had to subtract \(8000\) from the value to get the interest first. This could possibly be a result of the way the formula is given in the formula booklet so teachers need to be aware of this.

b.

Syllabus sections

Topic 1 - Number and algebra » 1.9 » Financial applications of geometric sequences and series: compound interest.
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