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Date May 2013 Marks available 3 Reference code 13M.1.sl.TZ1.14
Level SL only Paper 1 Time zone TZ1
Command term Find Question number 14 Adapted from N/A

Question

Jenny invested $20 000 in a bank account that paid 3.5 % annual simple interest. She withdrew her investment from the account when its value was $31 200.

Ramón invests $18 000 in a bank account that pays 3.4 % nominal annual interest, compounded quarterly.

Find the minimum number of years that Ramón must invest the money for his investment to be worth $27 000.

Markscheme

\(27000 = 18000{\left[ {1 + \frac{{3.4}}{{100 \times 4}}} \right]^{4n}}\)     (M1)(A1)


Note: Award (M1) for substituted compound interest formula, (A1) for correct substitutions.


\((n =) 12\)     (A1)     (C3)


Note: Correct answer only. If 11.976… seen award (A2).

Examiners report

Although this question was late in the paper there were a number of candidates who scored fullmarks. Others were able to do simple interest but not compound interest or vice versa. However there were a large number that scored zero.

Syllabus sections

Topic 1 - Number and algebra » 1.9 » Financial applications of geometric sequences and series: compound interest.
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