| Date | November 2008 | Marks available | 2 | Reference code | 08N.1.sl.TZ0.12 |
| Level | SL only | Paper | 1 | Time zone | TZ0 |
| Command term | Calculate | Question number | 12 | Adapted from | N/A |
Question
The diagram shows a pyramid VABCD which has a square base of length 10 cm and edges of length 13 cm. M is the midpoint of the side BC.
Calculate the length of VM.
[2]
a.
Calculate the vertical height of the pyramid.
[2]
b.
Markscheme
Unit penalty (UP) applies in this question.
VM2=132−52 (M1)
UP =12 cm (A1) (C2)
[2 marks]
a.
Unit penalty (UP) applies in this question.
h2=122−52 (or equivalent) (M1)
UP =10.9 cm (A1)(ft) (C2)
[2 marks]
b.
Examiners report
This question was poorly answered by many of the candidates. Pythagoras was improperly applied and candidates were unable to identify right angled triangles.
a.
This question was poorly answered by many of the candidates. Pythagoras was improperly applied and candidates were unable to identify right angled triangles.
b.
Syllabus sections
Topic 5 - Geometry and trigonometry » 5.4 » Geometry of three-dimensional solids: cuboid; right prism; right pyramid; right cone; cylinder; sphere; hemisphere; and combinations of these solids.
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