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Date May 2012 Marks available 3 Reference code 12M.1.sl.TZ2.1
Level SL only Paper 1 Time zone TZ2
Command term Deduce Question number 1 Adapted from N/A

Question

Consider c = 5200 and d = 0.0000037.

Write down the value of r = c × d.

 

[1]
a.

Write down your value of r in the form a × 10k, where 1 a < 10 and \(k \in \mathbb{Z}\).

[2]
b.

Consider the following statements about c, d and r. Only three of these statements are true.

Circle the true statements.

[3]
c.

Markscheme

r = 0.01924     (A1)     (C1)

Note: Accept 0.0192 and 0.019

[1 mark]

a.

r = 1.924 × 10−2     (A1)(ft)(A1)(ft)     (C2)

Notes: Award (A1) for 1.924, (A1) for 10−2. Accept 1.92 and 1.9. Follow through from their part (a).

[2 marks]

b.

     (A1)(A1)(A1)     (C3)

Notes: Award (A1) for each true statement circled. Do not follow through from part (a). Award (A1)(A1)(A0) if 1 extra term seen. Award (A1)(A0)(A0) if 2 extra terms seen. Award (A0)(A0)(A0) if all terms circled. Accept other indications of the correct statements i.e. highlighted or ticks.

[3 marks]

c.

Examiners report

Most candidates could find the value of r and give it in standard form, although some did not give it to the correct degree of accuracy. Some candidates gave a positive index and others used calculator notation rather than standard form.

a.

Most candidates could find the value of r and give it in standard form, although some did not give it to the correct degree of accuracy. Some candidates gave a positive index and others used calculator notation rather than standard form.

b.

There were a number of candidates who were unable to find the three true statements about set notation.

c.

Syllabus sections

Topic 1 - Number and algebra » 1.0 » Basic use of the four operations of arithmetic, using integers, decimals and fractions, including order of operations
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