Date | May 2012 | Marks available | 3 | Reference code | 12M.1.sl.TZ2.1 |
Level | SL only | Paper | 1 | Time zone | TZ2 |
Command term | Deduce | Question number | 1 | Adapted from | N/A |
Question
Consider c = 5200 and d = 0.0000037.
Write down the value of r = c × d.
Write down your value of r in the form a × 10k, where 1 ≤ a < 10 and \(k \in \mathbb{Z}\).
Consider the following statements about c, d and r. Only three of these statements are true.
Circle the true statements.
Markscheme
r = 0.01924 (A1) (C1)
Note: Accept 0.0192 and 0.019
[1 mark]
r = 1.924 × 10−2 (A1)(ft)(A1)(ft) (C2)
Notes: Award (A1) for 1.924, (A1) for 10−2. Accept 1.92 and 1.9. Follow through from their part (a).
[2 marks]
(A1)(A1)(A1) (C3)
Notes: Award (A1) for each true statement circled. Do not follow through from part (a). Award (A1)(A1)(A0) if 1 extra term seen. Award (A1)(A0)(A0) if 2 extra terms seen. Award (A0)(A0)(A0) if all terms circled. Accept other indications of the correct statements i.e. highlighted or ticks.
[3 marks]
Examiners report
Most candidates could find the value of r and give it in standard form, although some did not give it to the correct degree of accuracy. Some candidates gave a positive index and others used calculator notation rather than standard form.
Most candidates could find the value of r and give it in standard form, although some did not give it to the correct degree of accuracy. Some candidates gave a positive index and others used calculator notation rather than standard form.
There were a number of candidates who were unable to find the three true statements about set notation.