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Date November 2017 Marks available 4 Reference code 17N.2.sl.TZ0.5
Level SL only Paper 2 Time zone TZ0
Command term Use, Represent, and Draw Question number 5 Adapted from N/A

Question

A function \(f\) is given by \(f(x) = (2x + 2)(5 - {x^2})\).

The graph of the function \(g(x) = {5^x} + 6x - 6\) intersects the graph of \(f\).

Find the exact value of each of the zeros of \(f\).

[3]
a.

Expand the expression for \(f(x)\).

[1]
b.i.

Find \(f’(x)\).

[3]
b.ii.

Use your answer to part (b)(ii) to find the values of \(x\) for which \(f\) is increasing.

[3]
c.

Draw the graph of \(f\) for \( - 3 \leqslant x \leqslant 3\) and \( - 40 \leqslant y \leqslant 20\). Use a scale of 2 cm to represent 1 unit on the \(x\)-axis and 1 cm to represent 5 units on the \(y\)-axis.

[4]
d.

Write down the coordinates of the point of intersection.

[2]
e.

Markscheme

\( - 1,{\text{ }}\sqrt 5 ,{\text{ }} - \sqrt 5 \)     (A1)(A1)(A1)

 

Note:     Award (A1) for –1 and each exact value seen. Award at most (A1)(A0)(A1) for use of 2.23606… instead of \(\sqrt 5 \).

 

[3 marks]

a.

\(10x - 2{x^3} + 10 - 2{x^2}\)     (A1)

 

Notes:     The expansion may be seen in part (b)(ii).

 

[1 mark]

b.i.

\(10 - 6{x^2} - 4x\)     (A1)(ft)(A1)(ft)(A1)(ft)

 

Notes:     Follow through from part (b)(i). Award (A1)(ft) for each correct term. Award at most (A1)(ft)(A1)(ft)(A0) if extra terms are seen.

 

[3 marks]

b.ii.

\(10 - 6{x^2} - 4x > 0\)     (M1)

 

Notes:     Award (M1) for their \(f’(x) > 0\). Accept equality or weak inequality.

 

\( - 1.67 < x < 1{\text{ }}\left( { - \frac{5}{3} < x < 1,{\text{ }} - 1.66666 \ldots  < x < 1} \right)\)     (A1)(ft)(A1)(ft)(G2)

 

Notes:     Award (A1)(ft) for correct endpoints, (A1)(ft) for correct weak or strict inequalities. Follow through from part (b)(ii). Do not award any marks if there is no answer in part (b)(ii).

 

[3 marks]

c.

N17/5/MATSD/SP2/ENG/TZ0/05.d/M     (A1)(A1)(ft)(A1)(ft)(A1)

 

Notes:     Award (A1) for correct scale; axes labelled and drawn with a ruler.

Award (A1)(ft) for their correct \(x\)-intercepts in approximately correct location.

Award (A1) for correct minimum and maximum points in approximately correct location.

Award (A1) for a smooth continuous curve with approximate correct shape. The curve should be in the given domain.

Follow through from part (a) for the \(x\)-intercepts.

 

[4 marks]

d.

\((1.49,{\text{ }}13.9){\text{ }}\left( {(1.48702 \ldots ,{\text{ }}13.8714 \ldots )} \right)\)     (G1)(ft)(G1)(ft)

 

Notes:     Award (G1) for 1.49 and (G1) for 13.9 written as a coordinate pair. Award at most (G0)(G1) if parentheses are missing. Accept \(x = 1.49\) and \(y = 13.9\). Follow through from part (b)(i).

 

[2 marks]

e.

Examiners report

[N/A]
a.
[N/A]
b.i.
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b.ii.
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c.
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d.
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e.

Syllabus sections

Topic 7 - Introduction to differential calculus » 7.4 » Increasing and decreasing functions.
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