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Date November 2017 Marks available 1 Reference code 17N.2.sl.TZ0.5
Level SL only Paper 2 Time zone TZ0
Command term Expand Question number 5 Adapted from N/A

Question

A function f is given by f(x)=(2x+2)(5x2).

The graph of the function g(x)=5x+6x6 intersects the graph of f.

Find the exact value of each of the zeros of f.

[3]
a.

Expand the expression for f(x).

[1]
b.i.

Find f(x).

[3]
b.ii.

Use your answer to part (b)(ii) to find the values of x for which f is increasing.

[3]
c.

Draw the graph of f for 3 and - 40 \leqslant y \leqslant 20. Use a scale of 2 cm to represent 1 unit on the x-axis and 1 cm to represent 5 units on the y-axis.

[4]
d.

Write down the coordinates of the point of intersection.

[2]
e.

Markscheme

- 1,{\text{ }}\sqrt 5 ,{\text{ }} - \sqrt 5     (A1)(A1)(A1)

 

Note:     Award (A1) for –1 and each exact value seen. Award at most (A1)(A0)(A1) for use of 2.23606… instead of \sqrt 5 .

 

[3 marks]

a.

10x - 2{x^3} + 10 - 2{x^2}     (A1)

 

Notes:     The expansion may be seen in part (b)(ii).

 

[1 mark]

b.i.

10 - 6{x^2} - 4x     (A1)(ft)(A1)(ft)(A1)(ft)

 

Notes:     Follow through from part (b)(i). Award (A1)(ft) for each correct term. Award at most (A1)(ft)(A1)(ft)(A0) if extra terms are seen.

 

[3 marks]

b.ii.

10 - 6{x^2} - 4x > 0     (M1)

 

Notes:     Award (M1) for their f’(x) > 0. Accept equality or weak inequality.

 

- 1.67 < x < 1{\text{ }}\left( { - \frac{5}{3} < x < 1,{\text{ }} - 1.66666 \ldots  < x < 1} \right)     (A1)(ft)(A1)(ft)(G2)

 

Notes:     Award (A1)(ft) for correct endpoints, (A1)(ft) for correct weak or strict inequalities. Follow through from part (b)(ii). Do not award any marks if there is no answer in part (b)(ii).

 

[3 marks]

c.

N17/5/MATSD/SP2/ENG/TZ0/05.d/M     (A1)(A1)(ft)(A1)(ft)(A1)

 

Notes:     Award (A1) for correct scale; axes labelled and drawn with a ruler.

Award (A1)(ft) for their correct x-intercepts in approximately correct location.

Award (A1) for correct minimum and maximum points in approximately correct location.

Award (A1) for a smooth continuous curve with approximate correct shape. The curve should be in the given domain.

Follow through from part (a) for the x-intercepts.

 

[4 marks]

d.

(1.49,{\text{ }}13.9){\text{ }}\left( {(1.48702 \ldots ,{\text{ }}13.8714 \ldots )} \right)     (G1)(ft)(G1)(ft)

 

Notes:     Award (G1) for 1.49 and (G1) for 13.9 written as a coordinate pair. Award at most (G0)(G1) if parentheses are missing. Accept x = 1.49 and y = 13.9. Follow through from part (b)(i).

 

[2 marks]

e.

Examiners report

[N/A]
a.
[N/A]
b.i.
[N/A]
b.ii.
[N/A]
c.
[N/A]
d.
[N/A]
e.

Syllabus sections

Topic 7 - Introduction to differential calculus » 7.4 » Increasing and decreasing functions.
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