Find \(\left| {\overrightarrow {{\text{AB}}} } \right|\).

Let \(\overrightarrow {{\text{AC}}} = \left( {\begin{array}{*{20}{c}} 3 \\ 0 \\ 0 \end{array}} \right)\). Find \({\rm{B\hat AC}}\).

correct substitution     (A1)

eg\(\,\,\,\,\,\)\(\sqrt {{4^2} + {1^2} + {2^2}} \)

4.58257

\(\left| {\overrightarrow {{\text{AB}}} } \right| = \sqrt {21} \) (exact), 4.58     A1     N2

[2 marks]

finding scalar product and \(\left| {\overrightarrow {{\text{AC}}} } \right|\)     (A1)(A1)

scalar product \( = (4 \times 3) + (1 \times 0) + (2 \times 0){\text{ }}( = 12)\)

\(\left| {\overrightarrow {{\text{AC}}} } \right| = \sqrt {{3^2} + 0 + 0} {\text{ }}( = 3)\)

substituting their values into cosine formula     (M1)

eg cos B\(\hat A\)C\({\text{ = }}\frac{{4 \times 3 + 0 + 0}}{{\sqrt {{3^2}}  \times \sqrt {21} }},{\text{ }}\frac{4}{{\sqrt {21} }},{\text{ }}\cos \theta  = 0.873\)

0.509739 (29.2059°)

\({\rm{B\hat AC}} = 0.510\) (29.2°)     A1     N2

[4 marks]