Date | May 2022 | Marks available | 1 | Reference code | 22M.2.AHL.TZ2.4 |
Level | Additional Higher Level | Paper | Paper 2 | Time zone | Time zone 2 |
Command term | Find | Question number | 4 | Adapted from | N/A |
Question
A student investigating the relationship between chemical reactions and temperature finds the Arrhenius equation on the internet.
This equation links a variable with the temperature , where and are positive constants and .
The Arrhenius equation predicts that the graph of against is a straight line.
Write down
The following data are found for a particular reaction, where is measured in Kelvin and is measured in :
Find an estimate of
Show that is always positive.
Given that and , sketch the graph of against .
(i) the gradient of this line in terms of ;
(ii) the -intercept of this line in terms of .
Find the equation of the regression line for on .
.
It is not required to state units for this value.
.
It is not required to state units for this value.
Markscheme
attempt to use chain rule, including the differentiation of (M1)
A1
this is the product of positive quantities so must be positive R1
Note: The R1 may be awarded for correct argument from their derivative. R1 is not possible if their derivative is not always positive.
[3 marks]
A1A1A1
Note: Award A1 for an increasing graph, entirely in first quadrant, becoming concave down for larger values of , A1 for tending towards the origin and A1 for asymptote labelled at .
[3 marks]
taking of both sides OR substituting and (M1)
OR (A1)
(i) so gradient is A1
(ii) -intercept is A1
Note: The implied (M1) and (A1) can only be awarded if both correct answers are seen. Award zero if only one value is correct and no working is seen.
[4 marks]
an attempt to convert data to and (M1)
e.g. at least one correct row in the following table
line is A1
[2 marks]
A1
[1 mark]
attempt to rearrange or solve graphically (M1)
A1
Note: Accept an value of … from use of value.
[2 marks]
Examiners report
This question caused significant difficulties for many candidates and many did not even attempt the question. Very few candidates were able to differentiate the expression in part (a) resulting in difficulties for part (b). Responses to parts (c) to (e) illustrated a lack of understanding of linearizing a set of data. Those candidates that were able to do part (d) frequently lost a mark as their answer was given in x and y.