Date | May 2021 | Marks available | 1 | Reference code | 21M.1.AHL.TZ1.5 |
Level | Additional Higher Level | Paper | Paper 1 | Time zone | Time zone 1 |
Command term | Find | Question number | 5 | Adapted from | N/A |
Question
A garden has a triangular sunshade suspended from three points A(2, 0, 2), B(8, 0, 2)A(2, 0, 2), B(8, 0, 2) and C(5, 4, 3)C(5, 4, 3), relative to an origin in the corner of the garden. All distances are measured in metres.
Find →CA−−→CA.
Find →CB−−→CB.
Find →CA×→CB−−→CA×−−→CB.
Hence find the area of the triangle ABCABC.
Markscheme
→CA=(-3-4-1)−−→CA=⎛⎜⎝−3−4−1⎞⎟⎠ A1
[1 mark]
→CB=(3-4-1)−−→CB=⎛⎜⎝3−4−1⎞⎟⎠ A1
[1 mark]
→CA×→CB=(0-624)−−→CA×−−→CB=⎛⎜⎝0−624⎞⎟⎠ (M1)A1
Note: Do not award (M1) if less than 2 entries are correct.
[2 marks]
area is 12√62+242=12.4 m2 (12.3693…, 3√17)12√62+242=12.4 m2 (12.3693…, 3√17) (M1)A1
[2 marks]