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Date May 2021 Marks available 1 Reference code 21M.1.AHL.TZ1.5
Level Additional Higher Level Paper Paper 1 Time zone Time zone 1
Command term Find Question number 5 Adapted from N/A

Question

A garden has a triangular sunshade suspended from three points A(2, 0, 2), B(8, 0, 2)A(2, 0, 2), B(8, 0, 2) and C(5, 4, 3)C(5, 4, 3), relative to an origin in the corner of the garden. All distances are measured in metres.

Find CACA.

[1]
a.i.

Find CBCB.

[1]
a.ii.

Find CA×CBCA×CB.

[2]
b.

Hence find the area of the triangle ABCABC.

[2]
c.

Markscheme

CA=(-3-4-1)CA=341              A1


[1 mark]

a.i.

CB=(3-4-1)CB=341              A1


[1 mark]

a.ii.

CA×CB=(0-624)CA×CB=0624              (M1)A1


Note:
Do not award (M1) if less than 2 entries are correct.


[2 marks]

b.

area is 1262+242=12.4 m2  (12.3693, 317)1262+242=12.4 m2  (12.3693, 317)              (M1)A1


[2 marks]

c.

Examiners report

[N/A]
a.i.
[N/A]
a.ii.
[N/A]
b.
[N/A]
c.

Syllabus sections

Topic 3—Geometry and trigonometry » AHL 3.10—Vector definitions
Topic 3—Geometry and trigonometry

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