Date | November Example question | Marks available | 3 | Reference code | EXN.2.SL.TZ0.5 |
Level | Standard Level | Paper | Paper 2 | Time zone | Time zone 0 |
Command term | Hence or otherwise | Question number | 5 | Adapted from | N/A |
Question
The living accommodation on a university campus is in the shape of a rectangle with sides of length 200 m and 300 m.
There are three offices for the management of the accommodation set at the points A, B and C. These offices are responsible for all the students in the areas closest to the office. These areas are shown on the Voronoi diagram below. On this coordinate system the positions of A, B and C are (100, 160), (100, 40) and (250, 100) respectively.
The equation of the perpendicular bisector of [AC] is 5x-2y=615.
The manager of office C believes that he has more than one third of the area of the campus to manage.
Find the area of campus managed by office C.
Hence or otherwise find the areas managed by offices A and B.
State a further assumption that must be made in order to use area covered as a measure of whether or not the manager of office C is responsible for more students than the managers of offices A and B.
A new office is to be built within the triangle formed by A, B and C, at a point as far as possible from the other three offices.
Find the distance of this office from each of the other offices.
Markscheme
Divides area into two appropriate shapes
For example,
Area of triangle (12×200×40=) 4000 m2 (A1)
Area of rectangle (200×97)= 19400 m2 (A1)
23400 (m2) A1
Note: The area can be found using different divisions. Award A1 for any two correct areas found and A1 for the final answer.
[3 marks]
EITHER
200×300-234002=18300 m2 (M1)A1
OR
12×100×(203+163)=18300 m2 (M1)A1
THEN
Area managed by both offices A and B is 18300 m2 A1
[3 marks]
Density of accommodation/students is uniform R1
[1 mark]
250-163=87 (m) (M1)A1
Note: M1 is for an attempt to find the distance from the intersection point to one of the offices.
[2 marks]