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Date November 2018 Marks available 5 Reference code 18N.1.AHL.TZ0.H_4
Level Additional Higher Level Paper Paper 1 (without calculator) Time zone Time zone 0
Command term Find Question number H_4 Adapted from N/A

Question

Consider the following system of equations where aR.

2x+4yz=10

x+2y+az=5

5x+12y=2a.

Find the value of a for which the system of equations does not have a unique solution.

[2]
a.

Find the solution of the system of equations when a=2.

[5]
b.

Markscheme

* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.

an attempt at a valid method eg by inspection or row reduction       (M1)

2×R2=R12a=1

a=12      A1

 

[2 marks]

a.

using elimination or row reduction to eliminate one variable      (M1)

correct pair of equations in 2 variables, such as

5x+10y=255x+12y=4}      A1

Note: Award A1 for z = 0 and one other equation in two variables.

 

attempting to solve for these two variables      (M1)

x=26y=10.5,  z=0      A1A1

Note: Award A1A0 for only two correct values, and A0A0 for only one.

Note: Award marks in part (b) for equivalent steps seen in part (a).

 

[5 marks]

b.

Examiners report

[N/A]
a.
[N/A]
b.

Syllabus sections

Topic 1—Number and algebra » AHL 1.16—Solution of systems of linear equations
Topic 1—Number and algebra

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