| Date | May 2022 | Marks available | 1 | Reference code | 22M.1.SL.tz0.28 |
| Level | Standard Level | Paper | Paper 1 | Time zone | time zone 0 |
| Command term | Question number | 28 | Adapted from | N/A |
Question
A series of fitness tests were conducted before and after a training programme to evaluate the effectiveness of the programme. The table shows the mean results and probability (p) values.
Which fitness component shows no significant change?
A. Speed
B. Agility
C. Reaction time
D. Power
Markscheme
B
Examiners report
This was one of the more challenging questions on the paper. Most candidates discarded A as the answer. However, there was a relatively even distributed between selecting B, C & D. All p values answers are below 0.05 for A, C & D. However, B agility p value is above 0.07, therefore this demonstrated no significant change. Further review of this topic area in context is required. Consider offering similar style tables and graphs to support candidates drawing conclusion from data and applying their statistical knowledge and understanding.
Syllabus sections
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19M.2.HL:.tz0.1c:
Using the data, discuss the hypothesis that plyometric exercise can improve sprint performance.
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19N.1.SL.tz0.27:
What describes the difference between the two sets of group data in the table?
[Source: copyright International Baccalaureate Organization, 2019]
- 19N.2.HL:.tz0.1c: Using the statistical data, comment on the performance of trapping by the variable practice...
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19M.2.SL.tz0.1d:
Explain the reason for using a control condition in this study design.
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19M.2.HL:.tz0.1e:
Comment on the meaning of the results from the t-test.
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18N.2.SL.tz0.1a.iv:
A two-tailed, unpaired t-test was conducted on the data. The calculations yielded the following results:
- comparing low and moderate training level yielded p > 0.05
- comparing moderate and high training level yielded p < 0.05
- comparing low and high training level yielded p < 0.01.
Comment on the meaning of the results from the t-test.
