Date | November 2020 | Marks available | 1 | Reference code | 20N.3.SL.TZ0.5 |
Level | Standard level | Paper | Paper 3 | Time zone | 0 - no time zone |
Command term | Calculate | Question number | 5 | Adapted from | N/A |
Question
The spacetime diagram is in the reference frame of an observer O on Earth. Observer O and spaceship A are at the origin of the spacetime diagram when time . The worldline for spaceship A is shown.
Event E is the emission of a flash of light. Observer O sees light from the flash when years and calculates that event E is away, in the positive direction.
Calculate in terms of the velocity of spaceship A relative to observer O.
Draw the axis for the reference frame of spaceship A.
Plot the event E on the spacetime diagram and label it E.
Determine the time, according to spaceship A, when light from event E was observed on spaceship A.
Markscheme
✓
Accept if unit given.
line through origin and through one small square at this coordinate ✓
Answers shown for 5(a)(ii) and (b)(i) and (b)(ii).
X value of E at «» ✓
Y value of E at «» ✓
light cone from E «crosses at so» intersection on «on scale» ✓
✓
so « after leaving Earth» ✓
MP1 accept use of linear equations to find
Allow ECF from (b)(i) and (a)
Examiners report
Very well answered.
Most answers successfully drew the correct x' axis.
Event E is the event when the light is emitted (4,5). Some candidates missed that and placed it at (4,9).
To determine these coordinates candidates were expected to construct a light path from (0,9) which intercepts at x=4 and t=5. This is a very common mistake which needs careful explanation by teachers.
Those candidates who placed E at the correct position were then able to calculate the time appropriately.