User interface language: English | Español

Date November 2019 Marks available 2 Reference code 19N.2.SL.TZ0.5
Level Standard level Paper Paper 2 Time zone 0 - no time zone
Command term Calculate Question number 5 Adapted from N/A

Question

An electron is placed at a distance of 0.40 m from a fixed point charge of –6.0 mC.

 

Show that the electric field strength due to the point charge at the position of the electron is 3.4 × 108 N C–1.

[2]
a.

Calculate the magnitude of the initial acceleration of the electron.

[2]
b(i).

Describe the subsequent motion of the electron.

[3]
b(ii).

Markscheme

E=k×qr2 

E=8.99×109×6.0×10-30.42  OR  E=3.37×108 «NC-1» 

NOTE: Ignore any negative sign.

a.

F=q×E  OR  F=1.6×10-19×3.4×108=5.4×10-11«N»

a=«5.4×10-119.1×10-31=» 5.9×1019«ms-2»

NOTE: Ignore any negative sign.
Award [1] for a calculation leading to
a=«ms-2»
Award [2] for bald correct answer

 

b(i).

the electron moves away from the point charge/to the right «along the line joining them» ✔
decreasing acceleration ✔
increasing speed ✔

NOTE: Allow ECF from MP1 if a candidate mistakenly evaluates the force as attractive so concludes that the acceleration will increase

b(ii).

Examiners report

[N/A]
a.
[N/A]
b(i).
[N/A]
b(ii).

Syllabus sections

Core » Topic 5: Electricity and magnetism » 5.1 – Electric fields
Show 60 related questions
Core » Topic 2: Mechanics » 2.2 – Forces
Core » Topic 2: Mechanics
Core » Topic 5: Electricity and magnetism
Core

View options