The minor product, C₆H₅–CH₂–CH₂Br, can be directly converted to an intermediate compound, X, which can then be directly converted to the acid C₆H₅–CH₂–COOH.

C₆H₅–CH₂–CH₂Br → X → C₆H₅–CH₂–COOH

Identify X.

In which order should the reagents be used to convert benzene into phenylamine (aniline)?

State the reagents used in the two-stage conversion of nitrobenzene to aniline.

Sketch the mechanism for the reaction of propene with hydrogen bromide using curly arrows.

Propene is reacted first with hydrogen chloride to produce X which is then reacted with aqueous sodium hydroxide to give Y. Finally, Y is reacted with excess acidified potassium dichromate solution.

$$\text{C}{\text{H}}_{\text{3}}\text{CHC}{\text{H}}_{\text{2}}\stackrel{\text{HCL}}{\to }\text{X}\stackrel{\text{NaOH(aq)}}{\to }\text{Y}\stackrel{{\text{H}}^{+}/\text{C}{\text{r}}_2{{\text{O}}_7}^{2-}\text{(aq)}}{\to }\text{Z}$$

What is the major product, Z? 

A.     CH₃CH(OH)CH₃

B.     CH₃COCH₃

C.     CH₃CH₂CHO

D.     CH₃(CH₂)₂COOH

Propanone can be synthesized in two steps from propene.

Suggest why propanal is a minor product obtained from the synthetic route in (g)(i).

Propanone can be synthesized in two steps from propene. Suggest the synthetic route including all the necessary reactants and steps.

Explain why the major organic product is 2-bromopropane and not 1-bromopropane.

Explain why the major organic product is 2-bromopropane and not 1-bromopropane.