Date | May 2019 | Marks available | 3 | Reference code | 19M.2.sl.TZ1.5 |
Level | SL | Paper | 2 | Time zone | TZ1 |
Command term | Suggest | Question number | 5 | Adapted from | N/A |
Question
Both vinegar (a dilute aqueous solution of ethanoic acid) and bleach are used as cleaning agents.
Bleach reacts with ammonia, also used as a cleaning agent, to produce the poisonous compound chloramine, NH2Cl.
Outline why ethanoic acid is classified as a weak acid.
A solution of bleach can be made by reacting chlorine gas with a sodium hydroxide solution.
Cl2 (g) + 2NaOH (aq) NaOCl (aq) + NaCl (aq) + H2O (l)
Suggest, with reference to Le Châtelier’s principle, why it is dangerous to mix vinegar and bleach together as cleaners.
Draw a Lewis (electron dot) structure of chloramine.
Deduce the molecular geometry of chloramine and estimate its H–N–H bond angle.
Molecular geometry:
H–N–H bond angle:
Markscheme
partial dissociation «in aqueous solution» [✔]
ethanoic acid/vinegar reacts with NaOH [✔]
moves equilibrium to left/reactant side [✔]
releases Cl2 (g)/chlorine gas
OR
Cl2 (g)/chlorine gas is toxic [✔]
Note: Accept “ethanoic acid produces H+ ions”.
Accept “ethanoic acid/vinegar reacts with NaOCl”.
Do not accept “2CH3COOH + NaOCl + NaCl → 2CH3COONa + Cl2 + H2O” as it does not refer to equilibrium.
Accept suitable molecular or ionic equations for M1 and M3.
[✔]
Note: Accept any combination of dots/crosses or lines to represent electron pairs.
Molecular geometry:
«trigonal» pyramidal [✔]
H–N–H bond angle:
107° [✔]
Note: Accept angles in the range of 100–109.
Examiners report
The definition of a weak acid was generally correct.
Explaining why it was dangerous to mix chlorine with vinegar was not well answered but most students gained at least one mark for stating that “chlorine gas will be produced”, but couldn’t link it to equilibrium ideas.
The Lewis structure of chloramine was correct for strong candidates, but many made the mistake of omitting electron pairs on N and Cl.
The molecular geometry and bond angles often did not correspond to each other with quite a few candidates stating trigonal planar and then 107 for the angle.
Syllabus sections
-
18M.2.sl.TZ2.5a:
Distinguish between the terms reaction quotient, Q, and equilibrium constant, Kc.
- 22M.2.sl.TZ1.2c(iii): State how the use of a catalyst affects the position of the equilibrium.
-
22M.2.sl.TZ1.2c(i):
Deduce the expression for the equilibrium constant, Kc, for this equation.
-
22M.2.sl.TZ1.2c(ii):
Explain why an increase in pressure shifts the position of equilibrium towards the products and how this affects the value of the equilibrium constant, Kc.
-
22M.2.hl.TZ1.3a(i):
Deduce the expression for the equilibrium constant, Kc, for this equation.
-
22M.1.sl.TZ1.19:
Which species are acids in the equilibrium below?
CH3NH2 + H2O CH3NH3+ + OH–
A. CH3NH2 and H2O
B. H2O and CH3NH3+
C. H2O and OH–
D. CH3NH2 and CH3NH3+
- 17M.1.hl.TZ2.22: Which variable affects the equilibrium constant, Kc? A. Atmospheric pressure B. ...
-
22M.1.hl.TZ2.23:
0.50 mol of (g) and 0.50 mol of Br2 (g) are placed in a closed flask. The following equilibrium is established.
(g) + Br2 (g) 2Br (g)
The equilibrium mixture contains 0.80 mol of Br (g). What is the value of Kc?
A. 0.64
B. 1.3
C. 2.6
D. 64
-
19N.2.sl.TZ0.4a(iii):
The dissociation of citric acid is an endothermic process. State the effect on the hydrogen ion concentration, [H+], and on the equilibrium constant, of increasing the temperature.
- 19N.2.sl.TZ0.4a(ii): The value of the equilibrium constant for the first dissociation at 298 K is 5.01 ×...
-
19M.2.sl.TZ2.5a(iii):
When a bottle of carbonated water is opened, these equilibria are disturbed.
State, giving a reason, how a decrease in pressure affects the position of Equilibrium (1).
-
18M.2.hl.TZ1.1d.i:
State the equilibrium constant expression, Kc.
-
18M.1.hl.TZ1.22:
What is the effect of increasing the temperature in this reaction?
CO2(g) + H2O(l) H+(aq) + HCO3−(aq) ΔH < 0
A. The pH will decrease.
B. The pH will increase.
C. CO2 pressure will decrease.
D. The equilibrium position will shift to the right.
-
22M.2.hl.TZ2.4c:
State the equilibrium constant expression, Kc, for this reaction.
-
18N.1.sl.TZ0.18:
Consider the reaction:
2N2O (g) 2N2 (g) + O2 (g)
The values of Kc at different temperatures are:
Which statement is correct at higher temperature?
A. The forward reaction is favoured.
B. The reverse reaction is favoured.
C. The rate of the reverse reaction is greater than the rate of the forward reaction.
D. The concentration of both reactants and products increase.
-
18M.2.hl.TZ1.1d.ii:
Predict, with a reason, the effect on the equilibrium constant, Kc, when the temperature is increased.
-
17M.3.sl.TZ1.17c:
Outline, giving the appropriate equation(s), how increasing levels of carbon dioxide will affect the pH of the oceans.
-
18M.1.sl.TZ1.18:
The equilibrium constant for N2(g) + 3H2(g) 2NH3(g) is K.
What is the equilibrium constant for this equation?
2N2(g) + 6H2(g) 4NH3(g)
A. K
B. 2K
C. K2
D. 2K2
-
19M.1.hl.TZ2.22:
Consider the following equilibrium reaction.
2N2O (g) + O2 (g) 4NO (g) ΔH = +16 kJ
Which change will move the equilibrium to the right?
A. Decrease in pressure
B. Decrease in temperature
C. Increase in [NO]
D. Decrease in [O2]
- 17N.1.hl.TZ0.19: The enthalpy change for the dissolution of NH4NO3 is +26 kJ mol–1 at 25 °C. Which statement...
-
17M.3.sl.TZ2.1c.i:
The equilibrium expression for O2 exchange between the atmosphere and ocean is O2(g) O2(aq). Identify one factor which shifts the equilibrium to the right.
-
17N.2.sl.TZ0.5a:
The following reaction was allowed to reach equilibrium at 761 K.
H2 (g) + I2 (g) 2HI (g) ΔHθ < 0
Outline the effect, if any, of each of the following changes on the position of equilibrium, giving a reason in each case.
-
17M.1.sl.TZ2.18:
What is the equilibrium constant expression, Kc, for the following reaction?
2NH3(g) + 2O2(g) N2O(g) + 3H2O(g)
A.
B.
C.
D.
-
18M.2.hl.TZ2.6c.i:
Nitrogen oxide is in equilibrium with dinitrogen dioxide.
2NO(g) N2O2(g) ΔHΘ < 0
Deduce, giving a reason, the effect of increasing the temperature on the concentration of N2O2.
-
19M.1.sl.TZ2.18:
What is the equilibrium constant expression for the following equation?
2NO2 (g) + F2 (g) 2NO2F (g)
A.
B.
C.
D.
-
17N.1.sl.TZ0.18:
What will happen if the pressure is increased in the following reaction mixture at equilibrium?
CO2 (g) + H2O (l) H+ (aq) + HCO3− (aq)
A. The equilibrium will shift to the right and pH will decrease.
B. The equilibrium will shift to the right and pH will increase.
C. The equilibrium will shift to the left and pH will increase.
D. The equilibrium will shift to the left and pH will decrease.
- 21N.1.hl.TZ0.27: What is correct for pure hot water?
-
17M.2.sl.TZ1.4c:
Hydrazine reacts with water in a similar way to ammonia. Deduce an equation for the reaction of hydrazine with water.
-
19N.2.hl.TZ0.4a(iii):
The dissociation of citric acid is an endothermic process. State the effect on the hydrogen ion concentration, [H+], and on Ka, of increasing the temperature.
- 19N.2.hl.TZ0.4a(ii): The value of Ka at 298 K for the first dissociation is 5.01 × 10−4. State, giving a reason,...
-
21N.2.hl.TZ0.3c(v):
State the equilibrium constant expression, Kc, for this reaction.
-
17M.2.sl.TZ1.4b:
Ammonia reacts reversibly with water.
NH3(g) + H2O(l) NH4+(aq) + OH−(aq)
Explain the effect of adding H+(aq) ions on the position of the equilibrium.
-
18M.1.sl.TZ2.18:
Which factor does not affect the position of equilibrium in this reaction?
2NO2(g) N2O4(g) ΔH = −58 kJ mol−1
A. Change in volume of the container
B. Change in temperature
C. Addition of a catalyst
D. Change in pressure
-
16N.1.sl.TZ0.18:
What happens when the temperature of the following equilibrium system is increased?
CO(g) + 2H2(g) CH3OH(g) ΔHθ = -91kJ
-
17M.2.sl.TZ2.3a.i:
Deduce the equilibrium constant expression, Kc, for the decomposition of PCl5(g).
-
19M.2.sl.TZ2.5b(i):
Predict, referring to Equilibrium (2), how the added sodium hydrogencarbonate affects the pH.(Assume pressure and temperature remain constant.)
-
21M.2.sl.TZ2.2e:
Consider the following equilibrium reaction:
2SO2 (g) + O2 (g) 2SO3 (g)
State and explain how the equilibrium would be affected by increasing the volume of the reaction container at a constant temperature.
-
19N.1.sl.TZ0.19:
What effect does increasing both pressure and temperature have on the equilibrium constant, Kc?
N2 (g) + 3H2 (g) 2NH3 (g) ΔH = −45.9 kJ
A. Decreases
B. Increases
C. Remains constant
D. Cannot be predicted as effects are opposite
-
18N.2.sl.TZ0.5b:
0.200 mol sulfur dioxide, 0.300 mol oxygen and 0.500 mol sulfur trioxide were mixed in a 1.00 dm3 flask at 1000 K.
Predict the direction of the reaction showing your working.
-
19M.2.hl.TZ1.4c:
Comment on why peracetic acid, CH3COOOH, is always sold in solution with ethanoic acid and hydrogen peroxide.
H2O2 (aq) + CH3COOH (aq) ⇌ CH3COOOH (aq) + H2O (l)
-
19M.1.sl.TZ1.18:
Kc for 2N2O (g) 2N2 (g) + O2 (g) is 7.3 × 1034.
What is Kc for the following reaction, at the same temperature?
N2 (g) + O2 (g) N2O (g)
A. 7.3 × 1034
B.
C.
D.
-
16N.2.sl.TZ0.1a:
Ethane-1,2-diol can be formed according to the following reaction.
2CO (g) + 3H2 (g) HOCH2CH2OH (g)
(i) Deduce the equilibrium constant expression, Kc, for this reaction.
(ii) State how increasing the pressure of the reaction mixture at constant temperature will affect the position of equilibrium and the value of Kc.
Position of equilibrium:
Kc:
(iii) Calculate the enthalpy change, ΔHθ, in kJ, for this reaction using section 11 of the data booklet. The bond enthalpy of the carbon–oxygen bond in CO (g) is 1077kJmol-1.
(iv) The enthalpy change, ΔHθ, for the following similar reaction is –233.8 kJ.
2CO(g) + 3H2(g) HOCH2CH2OH (l)
Deduce why this value differs from your answer to (a)(iii).
-
18M.2.sl.TZ2.5b:
The equilibrium constant, Kc, is 0.282 at temperature T.
Deduce, showing your work, the direction of the initial reaction.
-
20N.1.sl.TZ0.18:
What is correct when temperature increases in this reaction at equilibrium?
- 22M.2.hl.TZ1.3a(ii): State how the use of a catalyst affects the position of the equilibrium.
-
22M.2.hl.TZ1.3b(iii):
Demonstrate that your answer to (b)(i) is consistent with the effect of an increase in temperature on the percentage yield, as shown in the graph.
-
19M.1.hl.TZ1.22:
Kc for 2N2O (g) 2N2 (g) + O2 (g) is 7.3 × 1034.
What is Kc for the following reaction, at the same temperature?
N2 (g) + O2 (g) N2O (g)
A. 7.3 × 1034
B.
C.
D.
-
19M.3.hl.TZ2.1b(i):
Suggest why the relationship between time and lead concentration for Cola at 16 °C is not linear.
-
19M.3.sl.TZ2.1b(i):
Suggest why the relationship between time and lead concentration for Cola at 16 °C is not linear.
-
19M.3.sl.TZ2.1c(i):
Lead(II) chloride, PbCl2, has very low solubility in water.
PbCl2 (s) Pb2+ (aq) + 2Cl− (aq)
Explain why the presence of chloride ions in beverages affects lead concentrations.
-
19M.3.hl.TZ2.1c(i):
Lead(II) chloride, PbCl2, has very low solubility in water.
PbCl2 (s) Pb2+ (aq) + 2Cl− (aq)
Explain why the presence of chloride ions in beverages affects lead concentrations.
-
17M.1.sl.TZ1.18:
Consider the equilibrium between N2O4(g) and NO2(g).
N2O4(g) 2NO2(g) ΔH = +58 kJmol−1
Which changes shift the position of equilibrium to the right?
A. I and II only
B. I and III only
C. II and III only
D. I, II and III
-
19M.2.hl.TZ1.5b:
A solution of bleach can be made by reacting chlorine gas with a sodium hydroxide solution.
Cl2 (g) + 2NaOH (aq) ⇌ NaOCl (aq) + NaCl (aq) + H2O (l)
Suggest, with reference to Le Châtelier’s principle, why it is dangerous to mix vinegar and bleach together as cleaners.
-
21M.1.sl.TZ1.18:
Which changes produce the greatest increase in the percentage conversion of methane?
CH4 (g) + H2O (g) CO (g) + 3H2 (g)
-
19M.2.hl.TZ2.5b:
When a bottle of carbonated water is opened, these equilibria are disturbed.
State, giving a reason, how a decrease in pressure affects the position of Equilibrium (1).
-
17M.3.sl.TZ2.14b.ii:
Describe how large amounts of CO2 could reduce the pH of the ocean using an equation to support your answer.
-
19M.2.hl.TZ2.5d(ii):
Predict, referring to Equilibrium (2), how the added sodium hydrogencarbonate affects the pH.(Assume pressure and temperature remain constant.)
-
18M.2.sl.TZ1.1d:
Urea can also be made by the direct combination of ammonia and carbon dioxide gases.
2NH3(g) + CO2(g) (H2N)2CO(g) + H2O(g) ΔH < 0
Predict, with a reason, the effect on the equilibrium constant, Kc, when the temperature is increased.
- 21M.2.hl.TZ1.4d(iv): State and explain the effect of increasing temperature on the value of Kc.
-
21M.2.hl.TZ1.4d(iii):
State the expression for Kc for this stage of the reaction.
- 21M.1.sl.TZ2.18: What effect does a catalyst have on the position of equilibrium and the value of the...
-
17M.2.sl.TZ2.3a.ii:
Deduce, giving a reason, the factor responsible for establishing the new equilibrium after 14 minutes.
-
21M.1.hl.TZ2.23:
Sulfur dioxide reacts with oxygen to form sulfur trioxide.
2SO2 (g) + O2 (g) 2SO3 (g) ΔH = −197 kJ
Which change increases the value of Kc?
A. increasing the temperature
B. decreasing the temperature
C. decreasing [SO2 (g)]
D. decreasing [SO3 (g)]
-
19M.2.sl.TZ1.4c:
Comment on why peracetic acid, CH3COOOH, is always sold in solution with ethanoic acid and hydrogen peroxide.
H2O2 (aq) + CH3COOH (aq) CH3COOOH (aq) + H2O (l)
-
21M.2.sl.TZ1.4d(ii):
State the expression for Kc for this stage of the reaction.
- 21M.2.sl.TZ1.4d(iii): State and explain the effect of increasing temperature on the value of Kc.
-
18N.2.hl.TZ0.5e:
0.200 mol sulfur dioxide, 0.300 mol oxygen and 0.500 mol sulfur trioxide were mixed in a 1.00 dm3 flask at 1000 K.
Predict the direction of the reaction showing your working.
- 22M.2.hl.TZ2.6b(ii): Explain the effect of increasing temperature on the yield of SO3.
-
17N.2.hl.TZ0.6a.i:
State the equilibrium constant expression, Kc , for this reaction.
-
21M.2.hl.TZ2.7a:
State the equilibrium constant expression, Kc, for the reaction above.
- 21M.2.hl.TZ2.7b: State and explain how the equilibrium would be affected by increasing the volume of the...
-
17M.3.sl.TZ2.2b.ii:
Suggest one improvement to the investigation.
-
16N.3.sl.TZ0.1b:
CT values are influenced by temperature and by pH. The table below shows the CT values for chlorine needed to achieve 99% inactivation of a specific bacterium at stated values of pH and temperature.
(i) With reference to the temperature data in the table, suggest why it may be more difficult to treat water effectively with chlorine in cold climates.
(ii) Sketch a graph on the axes below to show how the CT value (at any temperature) varies with pH.
(iii) Comment on the relative CT values at pH 6.0 and pH 9.0 at each temperature.
(iv) Chlorine reacts with water as follows:
Cl2 (g) + H2O (l) HOCl (aq) + HCl (aq)
HOCl (aq) OCl− (aq) + H+ (aq)
Predict how the concentrations of each of the species HOCl (aq) and OCl− (aq) will change if the pH of the disinfected water increases.
-
20N.2.sl.TZ0.2d:
The equilibrium constant, , for the conversion of A to B is in water at .
Deduce, giving a reason, which compound, A or B, is present in greater concentration when equilibrium is reached.
-
20N.2.hl.TZ0.2f(i):
The equilibrium constant, , for the conversion of A to B is in water at .
Deduce, giving a reason, which compound, A or B, is present in greater concentration when equilibrium is reached.
-
18M.1.hl.TZ2.23:
What occurs when the pressure on the given equilibrium is increased at constant temperature?
N2(g) + O2(g) 2NO(g) ΔH = +180 kJ
A. Kc increases and the position of equilibrium moves to the right.
B. Kc stays the same and the position of equilibrium is unchanged.
C. Kc stays the same and the position of equilibrium moves to the left.
D. Kc decreases and the position of equilibrium moves to the left.
-
20N.2.hl.TZ0.5c:
State the expression for ethanoic acid.
- 20N.3.sl.TZ0.2b: The ice bath is used at equilibrium to slow down the forward and reverse reactions. Explain...
- 20N.3.sl.TZ0.2c: Suggest why the titration must be conducted quickly even though a low temperature is maintained.
- 22M.2.sl.TZ2.3b(ii): Explain the effect of increasing temperature on the yield of SO3.
-
17M.3.sl.TZ1.20b:
Explain the effect of a large amount of aspirin on the pH of blood.
-
22M.1.hl.TZ1.23:
At equilibrium, the concentrations of chlorine and iodine are both 0.02 mol dm–3.
Cl2 (g) + (g) Cl (g) Kc = 454
What is the concentration of iodine monochloride, Cl?
A.B.
C.
D.
-
22M.1.sl.TZ1.18:
Cl2 (g) + (g) Cl (g) Kc = 454
What is the Kc value for the reaction below?
2 Cl (g) Cl2 (g) + (g)
A.
B.
C.
D.
-
22M.2.hl.TZ1.3a(iii):
With reference to the reaction quotient, Q, explain why the percentage yield increases as the pressure is increased at constant temperature.
-
22M.1.sl.TZ2.18:
The equilibrium constant, Kc, for the reaction 2A + 4B 2C + 4D has a value of 4.0. What is the value of Kc for the reaction below at the same temperature?
C + 2D A + 2B
A. 0.25
B. 0.50
C. 1.0
D. 16
-
21N.1.sl.TZ0.19:
The equilibrium 2H2 (g) + N2 (g) N2H4 (g) has an equilibrium constant, K, at 150 °C.
What is the equilibrium constant at 150 °C, for the reverse reaction?
N2H4 (g) 2H2 (g) + N2 (g)
A. KB. K−1
C. −K
D. 2K
-
21N.2.sl.TZ0.3c(ii):
State the equilibrium constant expression, Kc, for this reaction.
- 21N.2.hl.TZ0.3c(vi): State, with a reason, the effect of an increase in temperature on the position of this...
-
21N.1.hl.TZ0.22:
A reversible reaction has a reaction quotient, Q, of 4.5 and equilibrium constant, Kc, of 6.2.
2A (g) A2 (g)
Which statement describes the reaction at this time?
A. The system has reached equilibrium.B. The rate of the forward reaction is greater than the rate of the reverse reaction.
C. The concentration of reactant is greater than the concentration of product.
D. At equilibrium, the concentration of reactant is greater than the concentration of product.
- 21N.2.sl.TZ0.3c(iii): State, with a reason, the effect of an increase in temperature on the position of this...