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Date May 2009 Marks available 2 Reference code 09M.2.hl.TZ2.4
Level HL only Paper 2 Time zone TZ2
Command term Describe Question number 4 Adapted from N/A

Question

The graph of y=ln(x) is transformed into the graph of y=ln(2x+1) .

Describe two transformations that are required to do this.

[2]
a.

Solve ln(2x+1)>3cos(x), x[0,10].

[4]
b.

Markscheme

EITHER

translation of 12 parallel to the x-axis

stretch of a scale factor of 12 parallel to the x-axis     A1A1

OR

stretch of a scale factor of 12 parallel to the x-axis

translation of 1 parallel to the x-axis     A1A1

Note: Accept clear alternative terminologies for either transformation.

[2 marks]

a.

EITHER

1.16<x<5.716.75<x10     A1A1A1A1

OR

]1.16, 5.71   ]6.75, 10]     A1A1A1A1

Note: Award A1 for 1 intersection value, A1 for the other 2, A1A1 for the intervals.

[6 marks]

b.

Examiners report

This question was well done by many candidates. It would appear, however, that few candidates were aware of the standard terminology – Stretch and Translation - used to describe the relevant graph transformations. Most made good use of a GDC to find the critical points and to help in deciding on the correct intervals. A significant minority failed to note x=10 as an endpoint.

a.

This question was well done by many candidates. It would appear, however, that few candidates were aware of the standard terminology – Stretch and Translation - used to describe the relevant graph transformations. Most made good use of a GDC to find the critical points and to help in deciding on the correct intervals. A significant minority failed to note x=10 as an endpoint.

b.

Syllabus sections

Topic 2 - Core: Functions and equations » 2.3 » Transformations of graphs: translations; stretches; reflections in the axes.

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