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Date November 2010 Marks available 8 Reference code 10N.3srg.hl.TZ0.5
Level HL only Paper Paper 3 Sets, relations and groups Time zone TZ0
Command term Show that Question number 5 Adapted from N/A

Question

Let \(\{ G,{\text{ }} * \} \) be a finite group that contains an element a (that is not the identity element) and \(H = \{ {a^n}|n \in {\mathbb{Z}^ + }\} \), where \({a^2} = a * a,{\text{ }}{a^3} = a * a * a\) etc.

Show that \(\{ H,{\text{ }} * \} \) is a subgroup of \(\{ G,{\text{ }} * \} \).

Markscheme

since G is closed, H will be a subset of G

closure: \(p,{\text{ }}q \in H \Rightarrow p = {a^r},{\text{ }}q = {a^s},{\text{ }}r,{\text{ }}s \in {\mathbb{Z}^ + }\)     A1

\(p * q = {a^r} * {a^s} = {a^{r + s}}\)     A1

\(r + s \in {\mathbb{Z}^ + } \Rightarrow p * q \in H\) hence H is closed     R1

associativity follows since \( * \) is associative on G     (R1)

EITHER

identity: let the order of a in G be \(m \in {\mathbb{Z}^ + },{\text{ }}m \geqslant 2\)     M1

then \({a^m} = e \in H\)     R1

inverses: \({a^{m - 1}} * a = e \Rightarrow {a^{m - 1}}\) is the inverse of a     A1

\({({a^{m - 1}})^n} * {a^n} = e\), showing that \({a^n}\) has an inverse in H     R1

hence H is a subgroup of G     AG

OR

since \((G,{\text{ }} * )\) is a finite group, and H is a non-empty closed subset of G, then \((H,{\text{ }} * )\) is

a subgroup of \((G,{\text{ }} * )\)     R4

Note: To receive the R4, the candidate must explicitly state the theorem, i.e. the three given conditions, and conclusion.

 

[8 marks]

Examiners report

This question was generally answered very poorly, if attempted at all. Candidates failed to realize that the property of closure needed to be properly proved. Others used negative indices when the question specifically states that the indices are positive integers.

Syllabus sections

Topic 8 - Option: Sets, relations and groups » 8.11 » Subgroups, proper subgroups.

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