User interface language: English | Español

Date May 2015 Marks available 2 Reference code 15M.2.hl.TZ2.2
Level HL only Paper 2 Time zone TZ2
Command term Determine Question number 2 Adapted from N/A

Question

From a group of five males and six females, four people are chosen.

Determine how many possible groups can be chosen.

[2]
a.

Determine how many groups can be formed consisting of two males and two females.

[2]
b.

Determine how many groups can be formed consisting of at least one female.

[2]
c.

Markscheme

\(\left( \begin{array}{l}
11\\
4
\end{array} \right)\) \( = \frac{{11 \times 10 \times 9 \times 8}}{{4 \times 3 \times 2 \times 1}} = 330\)     (M1)A1

[2 marks]

a.

 

 

\(\left( \begin{array}{l}
5\\
2
\end{array} \right) \times \left( \begin{array}{l}
6\\
2
\end{array} \right) = \frac{{5 \times 4}}{{2 \times 1}} \times \frac{{6 \times 5}}{{2 \times 1}}\)     M1

\( = 150\)     A1

[2 marks]

b.

METHOD 1

number of ways all men \( = \) \(\left( \begin{array}{l}
5\\
4
\end{array} \right) = 5\)

\(330 - 5 = 325\)     M1A1

 

Note:     Allow FT from answer obtained in part (a).

[2 marks]

 

METHOD 2

\(\left( \begin{array}{l}
6\\
1
\end{array} \right)\left( \begin{array}{l}
5\\
3
\end{array} \right) + \left( \begin{array}{l}
6\\
2
\end{array} \right)\left( \begin{array}{l}
5\\
2
\end{array} \right) + \left( \begin{array}{l}
6\\
3
\end{array} \right)\left( \begin{array}{l}
5\\
1
\end{array} \right) + \left( \begin{array}{l}
6\\
4
\end{array} \right)\)     M1

\( = 325\)     A1

[2 marks]

Total [6 marks]

c.

Examiners report

[N/A]
a.
[N/A]
b.
[N/A]
c.

Syllabus sections

Topic 1 - Core: Algebra » 1.3 » Counting principles, including permutations and combinations.

View options