Date | May 2009 | Marks available | 7 | Reference code | 09M.3srg.hl.TZ0.5 |
Level | HL only | Paper | Paper 3 Sets, relations and groups | Time zone | TZ0 |
Command term | Prove | Question number | 5 | Adapted from | N/A |
Question
Prove that set difference is not associative.
Markscheme
we are trying to prove (A∖B)∖C≠A∖(B∖C) M1(A1)
LHS=(A∩B′)∖C (A1)
=(A∩B′)∩C′ A1
RHS=A∖(B∩C′)
=A∩(B∩C′)′ (A1)
=A∩(B′∪C) A1
as LHS does not contain any element of C and RHS does, LHS≠RHS R1
hence set difference is not associative AG
Note: Accept answers which use a proof containing a counter example.
Total [7 marks]
Examiners report
This question was found difficult by a large number of candidates, but a number of correct solutions were seen. A number of candidates who understood what was required failed to gain the final reasoning mark. Many candidates seemed to be ill-prepared to deal with this style of question.